Note: Although the video is not provided in this question, it is not needed to answer the question.
Answer:
B) It does not deflect at all
Explanation:
Since both half shells contain opposite charges, the two shells become electrically neutral when they are brought together and the electroscope discharges. On separating the two half shells again, the needle does not deflect because the half shells have now lost their charges to become neutral.
Answer:
11.7 m
Explanation:
I assume north is the y direction and x is the east direction, so Δx refers to the displacement in the east direction.
First, find the time it takes for the velocity to change from directly north to directly east.
Given (in the y direction):
v₀ = 2.88 m/s
v = 0 m/s
a = 0.350 m/s² sin(-52.0°) = -0.276 m/s²
Find: t
v = at + v₀
(0 m/s) = (-0.276 m/s²) t + (2.88 m/s)
t = 10.4 s
Given (in the x direction):
v₀ = 0 m/s
a = 0.350 m/s² cos(-52.0°) = 0.215 m/s²
t = 10.4 s
Find: Δx
Δx = v₀ t + ½ at²
Δx = (0 m/s) (10.4 s) + ½ (0.215 m/s²) (10.4 s)²
Δx = 11.7 m
Answer:
a) P' = P_original, b) P ’= P_original + ρ g Δh
Explanation:
The expression for nanometric pressure is
P = ρ g h
where ρ is the density of the liquid and h is the height
a) we change the radius of the barrel, but keeping the same height
as the pressure does not depend on the radius it remains the same
P' = P_original
b) We change the barrel height
h ’≠ h
we substitute in the equation
P ’= ρ g h’
h ’= h + Δh
P ’= ρ g (h + Δh)
P ’= (ρ g h) + ρ g Δh
P ’= P_original + ΔP
In this case, the pressure changes due to the new height,
*if it is higher than the initial one, the pressure increases
*if the height is less than the initial one, the pressure is less
Answer:
Force to stretch the wire is 250 N
Explanation:
As we know that modulus of elasticity will remain the same for the wire if the applied stretch to the wire is within elastic limit
So we will have
now we have
so we can write it as
