Answer:
The displacement is 
The distance is 
Explanation:
From the question we are told that
The height from which the ball is dropped is 
The height attained at the first bounce is 
The height attained at the second bounce is 
The height attained at the third bounce is 
Note : When calculating displacement we consider the direction of motion
Generally given that upward is positive the total displacement of the ball is mathematically represented as
Here the 0 show that there was no bounce back to the point where Billy released the ball
=>
Generally the distance covered by the ball is mathematically represented as
The 2 shows that the ball traveled the height two times
=>
Newton’s third law is a force is a push or pull that acts upon an object as a result of another object.. A shot gun when fired pulls back when a force (you pulling the trigger) is acted upon it. This is how it relates. A rifle has less kick than a shot gun because the rifle is smaller and has less of a force than a shot gun.
Kepler's third law hypothesizes that for all the small bodies in orbit around the
same central body, the ratio of (orbital period squared) / (orbital radius cubed)
is the same number.
<u>Moon #1:</u> (1.262 days)² / (2.346 x 10^4 km)³
<u>Moon #2:</u> (orbital period)² / (9.378 x 10^3 km)³
If Kepler knew what he was talking about ... and Newton showed that he did ...
then these two fractions are equal, and may be written as a proportion.
Cross multiply the proportion:
(orbital period)² x (2.346 x 10^4)³ = (1.262 days)² x (9.378 x 10^3)³
Divide each side by (2.346 x 10^4)³:
(Orbital period)² = (1.262 days)² x (9.378 x 10^3 km)³ / (2.346 x 10^4 km)³
= 0.1017 day²
Orbital period = <u>0.319 Earth day</u> = about 7.6 hours.
Answer:
Explanation:
Given that height of the projectile as a function of time is
here we know that
h = 147 ft
so from above equation
now by solving above quadratic equation we know that
