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Bond [772]
3 years ago
14

A block slides on a frictionless, horizontal surface with a speed of 1.32 m/s. The block encounters an unstretched spring and co

mpresses it. If it takes the block 0.4 s to come to rest, what would be hte period of oscillation if the block stays stuck to the spring? If the spring extends back the other direction, the block eventually loses contatct with the psring and slides away, what is the velocity of the block when it loses contact with the spring?
Physics
1 answer:
Rus_ich [418]3 years ago
3 0

Answer:

Explanation:

The given time is 1 / 4 of the time period

So Time period  of oscillation.

= 4 x .4 =1.6 s

When the block reaches back its original position when it came in contact with the spring for the first time , the block and the spring will have maximum

velocity. After that spring starts unstretching , reducing its speed , so block loses contact as its velocity is not reduced .

So required velocity is the maximum velocity of the block while remaining in contact with the spring.

v ( max ) = w A = 1.32  m /s.

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iren2701 [21]
(2.00 hours) x (3,600 seconds/hour)  =  7,200 seconds

(9.00 minutes) x (60 seconds/minute)  =  540 seconds

The record time = (7,200 + 540 + 21) = 7,761 seconds

Distance  =  (speed) x (time)

                 = (5.436 m/s) x (7,761 sec)  =<span>  42,188.8 meters
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The official length of the marathon run is  42,195 meters.
If we divide that by the record time in the question, we get

                       5.4368... m/s .

Rounded to the nearest thousandth, that's  5.437 m/s.

If the question had given the speed as  5.437  instead of  5.436 ,
then we would have calculated the distance to be 

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4.6 meters closer to the official distance than the answer we did get.
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3 years ago
The position of a 50 g oscillating mass is given by x(t)=(2.0cm)cos(10t−π/4), where t is in s. If necessary, round your answers
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For the answer to the question above, this is the maximum displacement, the spring has only elastic potential energy.
spring is constant @ 5 N/m
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Write the physics equation for this graph in slope-intercept form (y=mx+b), expressed in terms of the appropriate variables.
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The equation that describes the graph is y = 16.7x + 150.

<h3>What is the equation?</h3>

We have been given the graph of a certain function data set in physics. We know that the graph is the representation of data on cartesian coordinates. In this case, we are asked to find the equation of the graph in the form; y=mx+b

m = slope of the graph

b = intercept of the graph.

To obtain the slope;

m = y2 - y1/ x2 - x1

m = 400 - 200/ 16 - 4

m = 200/ 12

m = 16.7

Then we can see from the graph that the y - intercept is 150. Having these data, the equation that could describe the graph is now;

y = 16.7x + 150

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A soccer ball is kicked from the top of one building with a height of H1 = 30.2 m to another building with a height of H2 = 12.0
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The amount of energy lost to air friction, given the data is 37.71 J

<h3>How to obtain the initial energy</h3>
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E₁ = ½ × 0.45 × 15.1²

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