Updrafts and downdrafts in a thunderstorm interacting with wind shear
Answer:
(a)
(b)
(c)
Explanation:
First change the units of the velocity, using these equivalents and
The angular acceleration the time rate of change of the angular speed according to:
Where is the original velocity, in the case the velocity before starting the deceleration, and is the final velocity, equal to zero because it has stopped.
b) To find the distance traveled in radians use the formula:
To change this result to inches, solve the angular displacement for the distance traveled ( is the radius).
c) The displacement is the difference between the original position and the final. But in every complete rotation of the rim, the point returns to its original position. so is needed to know how many rotations did the point in the 890.16 rad of distant traveled:
The real difference is in the 0.6667 (or 2/3) of the rotation. To find the distance between these positions imagine a triangle formed with the center of the blade (point C), the initial position (point A) and the final position (point B). The angle is between the two sides known. Using the theorem of the cosine we can find the missing side of the the triangle(which is also the net displacement):
Answer:
Resistance is inversely proportional to current, so when the resistance doubles, the current is cut in half. Resistance is directly proportional to current, so when the resistance doubles, the current is cut in half.
The change in angular displacement as a function of time is the definition given for angular velocity, this is mathematically described as
Here,
= Angular displacement
t = time
The angular velocity is given as
PART A) The angular velocity in SI Units will be,
PART B) From our first equation we can rearrange to find the angular displacement then
Replacing,
Answer:
(a) V = 0.75 m/s
(b) V = 0.125 m/s
Explanation:
The speed of the flow of the river can be given by following formula:
V = Q/A
V = Q/w d
where,
V = Speed of Flow of River
Q = Volume Flow Rate of River
w = width of river
d = depth of river
A = Area of Cross-Section of River = w d
(a)
Here,
Q = (300,000 L/s)(0.001 m³/1 L) = 300 m³/s
w = 20 m
d = 20 m
Therefore,
V = (300 m³/s)/(20 m)(20 m)
<u>V = 0.75 m/s</u>
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(b)
Here,
Q = (300,000 L/s)(0.001 m³/1 L) = 300 m³/s
w = 60 m
d = 40 m
Therefore,
V = (300 m³/s)/(60 m)(40 m)
<u>V = 0.125 m/s</u>