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3 years ago

How can you tell if something is a function or not a function

2 answers:

7 0

<span>This characteristic of non-functions was noticed by I-don't-know-who, and was codified in "The Vertical Line Test": Given the graph of a relation, if you can draw a vertical line that crosses the graph in more than one place, then the relation is not a function.</span>

NeTakaya3 years ago

4 0

Also, if you can get all the coordinates----> (3,5)
3=x value
5=y value

If the x value ever appears more than once then it's not a function
Example (1,5) (2,6) (3,9) (2,4)
Is that a function?
No, because the x value, 2 appears twice.

Example: (4,5) (2,3) (1,5) (3,7)
Is that a function?
Yes, because non of the x values appear more than once, there for the vertical line test will nvr have 2 intersections

Hope this helps!

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Hello, and good morning ppl!!<br> what´s <img src="https://tex.z-dn.net/?f=%5Csqrt%7B70%2A%2070%7D" id="TexFormula1" title="\sqr

Tamiku [17]

your question :

$\sqrt{70 \times 70}$

here's the solution,

=》

$\sqrt{10 \times 7 \times 10 \times 7}$

=》

$10 \times 7$

=》

$70$

i hope it helped you..... good luch for your English exam.....

4 0

2 years ago

Read 2 more answers

Which of the following is not a property of a chi-square distribution?

laiz [17]

Answer:

c) Is not a property (hence (d) is not either)

Step-by-step explanation:

Remember that the chi square distribution with k degrees of freedom has this formula

$\chi_k^2 = \matchal{N}_1^2 + \matchal{N}_2^2 + ... + \, \matchal{N}_{k-1}^2 + \matchal{N}_k^2$

Where N₁ , N₂m .... $N_k$ are independent random variables with standard normal distribution. Since it is a sum of squares, then the chi square distribution cant take negative values, thus (c) is not true as property. Therefore, (d) cant be true either.

Since the chi square is a sum of squares of a symmetrical random variable, it is skewed to the right (values with big absolute value, either positive or negative, will represent a big weight for the graph that is not compensated with values near 0). This shows that (a) is true

The more degrees of freedom the chi square has, the less skewed to the right it is, up to the point of being almost symmetrical for high values of k. In fact, the Central Limit Theorem states that a chi sqare with n degrees of freedom, with n big, will have a distribution approximate to a Normal distribution, therefore, it is not very skewed for high values of n. As a conclusion, the shape of the distribution changes when the degrees of freedom increase, because the distribution is more symmetrical the higher the degrees of freedom are. Thus, (b) is true.

6 0

3 years ago

Randy school requires that there are two adult chaperones for every 18 students when the students go on a field trip to the muse

Viktor [21]

Use a proportion.

2 adults to 18 students is as x adults to 99 students.

2/18 = x/99

18x = 2 * 99

18x = 198

x = 11

Answer: 11 adults

8 0

3 years ago

Suppose that a chemist is mixing two acid solutions, one of 50% concentration and the other of 60% concentration. Which of th

Flura [38]

Mixing the two concentrations would give a new concentration which is in between 50 - 60% .

D. 63% cannot be obtained

8 0

3 years ago

A recent survey of 50 executives who were laid off during a recent recession revealed it took a mean of 26 weeks for them to fin

g100num [7]

Answer: $(24.28,\ 27.72)$

Step-by-step explanation:

Given : Sample size : $n=50$

Sample mean : $\overline{x}=26$

Standard deviation : $\sigma =6.2$

Significance level : $\alpha=1-0.95=0.05$

Critical value : $z_{\alpha/2}=1.96$

Formula to find the confidence interval for population mean :-

$\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}\\\\=26\pm(1.96)\dfrac{6.2}{\sqrt{50}}\\\\\approx26\pm1.72\\\\=(26-1.72,\ 26+1.72)\\\\=(24.28,\ 27.72)$

Hence, a 95% confidence interval for the population mean = $(24.28,\ 27.72)$

6 0

3 years ago