Question

You wish to make a 0.289 M hydroiodic acid solution from a stock solution of 3.00 M hydroiodic acid. How much concentrated acid must you add to obtain a total volume of 100 mL of the dilute solution

Answer 1

Answer:

$V_1=9.63mL$

Explanation:

Hello,

In this case, we work on a dilution process in which we can state that the moles remain the same after the dilution process. In such a way, we can write:

$n_1=n_2$

That in terms of molarities and volumes is:

$M_1V_1=M_2V_2$

Whereas $M_1$ is the initial molarity (3.00 M) of the stock solution, $M_2$ the molarity of the diluted solution (0.289 M), $V_1$ the aliquot of the stock (concentrated) solution and $V_2$ the volume of the diluted solution (100 mL), thus, we compute $V_1$ as required:

$V_1=\frac{M_2V_2}{M_1} =\frac{0.289M*100mL}{3.00M} \\\\V_1=9.63mL$

Best regards.