Alice added sodium chloride to water and stirred the water for several minutes. Alice is most likely trying to demonstrate that
ionic compounds
1. are hard.
2. can dissolve.
3. are clear.
4. can melt.
1. are hard.
2. can dissolve.
3. are clear.
4. can melt.
1 answer:
Answer:
2. can dissolve.
Explanation:
Ionic compounds are compound that have a positive charge and a negative charge. The compound have cations and anions. Base on the question sodium chloride is an Ionic compound . The sodium produces the cation ions (Na+) while the chlorine produces the anions (Cl-). Generally, ionic compound has a strong bond.
Stirring sodium chloride in water, Alice is most likely to demonstrate the ability of ionic compound to dissolve in water. Ionic compounds dissolves in polar solvent like water. The opposite charge present in the ionic compound are usually dissociated when they are immersed in water. The cations of sodium are surrounded by the negatively charged oxygen ion while the anions of chlorine are surrounded by the positively charged hydrogen ion. The water molecules surround the ions available in the ionic compound thereby preventing it from recombining. All of the water molecules surround the ions of the ionic compound to dissolve it.
The picture above demonstrate how NaCl is dissolve in water.
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<u>Answer:</u> The volume of stock solution needed is 90 mL
<u>Explanation:</u>
To calculate the molarity of the diluted solution, we use the equation:
where,
are the molarity and volume of the stock sulfuric acid solution
are the molarity and volume of diluted sulfuric acid solution
We are given:
Putting values in above equation, we get:
Hence, the volume of stock solution needed is 90 mL
Complete Question
The complete question is shown on the first uploaded image
Answer:
X is Be
Y is B
Z is O
Explanation:
In order to understand the solution, we need to that the an element form a bond based on
1 The number of valence electron available in its atom
2 The number of electron it require to attains its stable state i.e its Octet state
The number of valence electron for each of the option are
F = 7, N = 5 , O = 6 , C = 4 , B = 3 , Be = 2
Considering the first element
We see that X is donating two valence electron in its atom and it is donating it to 2 Cl as Cl only requires a single electron to achieve its stable state
Now looking option we can see that Be has two valence electron in it atom and in order for it to attain its stable state it needs to release the electron so the correct option for this question is Be
Considering the second element
We see that Y is donating three valence electron in its atom and it is donating it to 3 Cl as Cl only requires a single electron to achieve its stable state
Now looking option we can see that B has three valence electron in it atom and in order for it to attain its stable state it needs to release the valence electron so the correct option for this question is B
Considering the second element
We see that Z is donating two valence electron in its atom and it is donating it to 2 Cl as Cl only requires a single electron to achieve its stable state, also Z has 2 lone-pair valence electron
Now looking at the option we can see that O has 6 valence electron so if it donates 2 valence electron it will still be left with 4 - pair of electron
Therefore the correct option to this question is O
