Answer:
2,347.8 grams
Explanation:
The freezing point depression Kf of water = 1.86° C / molal.
To still freeze at -12° C, then the molality of the solution 12/ 1.86 = 6.45 moles
The molecular weight of sorbitol (C6H14O6)is:
6 C = 6 ×12 = 72
14 H = 14 × 1 = 14
6 O = 6 × 16 = 96
...giving a total of 182
So one mole of sorbitol has a mass of 182 grams.
Since there are 2 kg of water, 2 × 6.45 moles = 12.9 moles can be added to the water to get the 12° C freezing point depression.
Therefore
grams = moles × molar mass
12.9 moles × 182 grams / mole = 2,347.8 grams of sorbitol can be added and still freeze
The answer is either 38 g or 40.g KCLO3. If it 95% instead of 895%.
Answer:
This depict that the growth of the new plant has taken place due to asexual form of reproduction.
Explanation:
A procedure in which new offspring is generated from a single parent without involving sex cells or gametes is known as asexual reproduction. One of the asexual forms of reproduction in plants is the artificial propagation of plants. The three general procedures of artificial propagation of plants are layering, cuttings, and grafting.
In cutting, a novel plant is developed by incising a small section of a plant that can be anything comprising bud on it. This section of the plant is then watered and grown into soil, and after some days a new plant begins to grow.
Answer:
Molecular formula = C₄H₆As₆Cu₄O₁₆
Explanation:
Given data:
Empirical formula = C₂H₃As₃Cu₂O₈
Molar mass of compound = 1013 g/mol
Molecular formula = ?
Solution:
Molecular formula = n (empirical formula)
n = molar mass of compound / empirical formula mass
Empirical formula mass of C₂H₃As₃Cu₂O₈ is 506.897 g/mol
by putting values.
n = 1013 / 506.897
n = 2
Molecular formula = n (empirical formula)
Molecular formula = 2 (C₂H₃As₃Cu₂O₈)
Molecular formula = C₄H₆As₆Cu₄O₁₆
