What is the mass of 11.5 liters of CL2 gas at STP?

1 answer:

6 0

At STP, the volume of Cl2 is 22.4 L/mol.

11.5 L Cl2 * (1 mol Cl2/ 22.4 L Cl2)= 115/224 mol Cl2.

115/224 mol Cl2* (70.90 g Cl2/ 1 mol Cl2)= 36.4 g Cl2.

The final answer is 36.4 g Cl2.

Hope this helps~

You might be interested in

Which processes are part of the fast carbon cycle?

SVETLANKA909090 [29]

Answer:

B) Transportation and photosynthesis

C) Cellular respiration and photosynthesis

6 0

3 years ago

What do many employers require of respiratory technician? Check all that apply.

meriva

Answer:

1 & 4

Explanation:

just got it right on edge

6 0

3 years ago

Graphite and iodine are non metal but they shine why secondry school

Alex_Xolod [135]

It is their properties. it is made up naturally due to the ions

8 0

3 years ago

How can we make use of acids or bases to Prevent the growth of microorganisms in swimming pools?

pentagon [3]

By putting smarticle particles

8 0

4 years ago

What is the volume of 0.80 grams of o2 gas at stp? (5 points) group of answer choices 0.59 liters 0.56 liters 0.50 liters 0.47 l

Vladimir [108]

Answer:

0.56L

Explanation:

This question requires the Ideal Gas Law: $PV=nRT$ where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of the gas, R is the Ideal Gas constant, and T is the Temperature of the gas.

Since all of the answer choices are given in units of Liters, it will be convenient to use a value for R that contains "Liters" in its units: $R=0.0821\frac{L\cdot atm}{mol\cdot K}$

Since the conditions are stated to be STP, we must remember that STP is Standard Temperature Pressure, which means $T=273.15K$ and $P=1atm$

Lastly, we must calculate the number of moles of $O_2(g)$ there are. Given 0.80g of $O_2(g)$ , we will need to convert with the molar mass of $O_2(g)$ . Noting that there are 2 oxygen atoms, we find the atomic mass of O from the periodic table (16g/mol) and multiply by 2: $32g\text{ }O_2=1mol\text{ }O_2$