1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
gogolik [260]
3 years ago
10

a 58.215 g sample of a pure metal is brought to 99.0c and added o 41.202 g of water at 21.5c in a calorimeter. if the metal and

water arrive at a final, equal temerature of 27.2c find a) the specific heat of the metal, and b) the approximate molar mass of yhe metal

Chemistry
2 answers:
rewona [7]3 years ago
7 0

Answer:

\boxed{\text{(a) 0.236 J$^{\circ}$C$^{-1}$g$^{-1}$; (b) 106 g/mol}}  

Explanation:

a) Specific heat capacity of the metal

The guiding principle in calorimetry is the Law of Conservation of Energy: the sum of all the energy transfers must add up to zero. That is,

q₁ + q₂ + … = 0

The formula for the heat q gained or lost by a substance is

q = mCΔT

where

 m = the mass of the substance.

 C = its specific heat capacity.

ΔT = the change in temperature.

In this problem, there are two heat transfers: the heat lost by the metal and the heat gained by the water.

m₁C₁ΔT₁ + m₂C₂ΔT₂ = 0

Data:  

m₁ = 58.215 g; T₁ = 99.0 °C; T₂ = 27.2 °C

m₂ = 41.202 g; T₁ = 21.5 °C; T₂ = 27.2 °C

Calculations:

ΔT₁ = 27.2 - 99.0 = -71.8 °C

ΔT₂ = 27.2 - 21.5 =    5.7 °C

\begin{array}{rcl}\text{heat lost by metal} + \text{heat gained by water} & = & 0\\m_{1}C_{1}\Delta T_{1} + m_{2}C_{2}\Delta T_{2}& = & 0\\\text{58.215 g $\times$ C$_{1} \times$ (-71.8 $^{\circ}\text{C}$)} + \text{41.202 g} \times 4.184 \text{ J$^{\circ}$C$^{-1}$g$^{-1}$} \times 5.75^{\circ}\text{C} & = & 0\\-4180C_{1}\text{ g}^{\circ}\text{C} + 987 \text{ J} & = & 0\\\end{array}\\

\begin{array}{rcl}-4180C_{1}\text{ g}^{\circ}\text{C}& = & -987 \text{ J}\\C_{1}& = & \dfrac{-987 \text{ J}}{-4180 \text{ g}^{\circ}\text{C}}\\\\& = & \textbf{0.236 J$^{\circ}$C$^{-1}$g$^{-1}$} \\\end{array}\\\text{The specific heat capacity of the metal is $\boxed{\textbf{0.236 J$^{\circ}$C$^{-1}$g$^{-1}$}}$}

b) Approximate molar mass of the metal

We could look up the metal that has the calculated specific heat capacity, but that would give the exact molar mass.

They asked for the approximate value, do they are probably expecting you to do something else.

Per the Law of Dulong and Petit, the molar specific heat capacity of a metal should be about 24.9 J·°C⁻¹mol⁻¹

\begin{array}{rcl}\text{0.236n J$^{\circ}$C$^{-1}$g$^{-1}$}  & = & \text{24.9 J$^{\circ}$C$^{-1}$mol$^{-1}$}\\\text{0.236n g$^{-1}$}  & = & \text{24.9 mol$^{-1}$}\\n & = & \dfrac{24.9\text{ mol}^{-1}}{0.236\text{ g}^{^{-1}}}\\\\&= &\textbf{106 g/mol}\\\end{array}\\\text{The approximate molar mass of the metal is $\large \boxed{\textbf{106 g/mol}}$}

Vinil7 [7]3 years ago
4 0

Answer:

The answer to your question is a)   C = 0.056 cal/g°C     b) 107.8 g/mol

Explanation:

I included a picture of the problem because it says that it has inappropriate words or links

You might be interested in
Electrons involved in bonding between atoms are____.
mariarad [96]

Answer:

valence electrons

8 0
3 years ago
Which of these molecules has an overall dipole moment? O A. F2 B. H2S C. CH4 D. CO2​
adelina 88 [10]

Answer:

i think the answer is B cus i think of that

4 0
2 years ago
Convert ethene to propanol​
klemol [59]

Answer:

The dehydration of ethanol Highlights Reductive Hydroformylation of ethene to propanol with homogeneous rhodium catalysts. Propane can be oxidized to propanol, and then dehydrated to form propene.

Explanation:

Always be happy!

:)

7 0
2 years ago
How many moles of N2 in 57.1 g of N2?
SpyIntel [72]

We are given –

  • Mass of \bf N_2 is 57.1 g and we are asked to find number of moles present in 57.1 g of \bf N_2

\qquad\pink{\bf\longrightarrow  { Molar \:mass \:of \: N_2:-}  }

\qquad\bf  \twoheadrightarrow 14\times 2

\qquad\bf \twoheadrightarrow   28

\qquad____________________

Now,Let's calculate the number of moles present in 57.1 g of \bf N_2

\qquad\purple{\bf\longrightarrow  { No \:of \:moles = \dfrac{Given \:mass}{Molar\: mass}}}

\qquad\bf   \twoheadrightarrow \dfrac{57.1}{28}

\qquad\bf  \twoheadrightarrow 2.04\: moles

__________________________________

7 0
2 years ago
Explain why fluorine and chlorine are in the same group of the periodic table.
Ivenika [448]

Answer:

They both have 7 electrons in their outer shell

8 0
2 years ago
Other questions:
  • How many moles are in 8.30x10^23 molecules of H2o
    7·2 answers
  • What are the four states of matter and explain them
    14·1 answer
  • The chemical symbol for sodium is
    9·1 answer
  • Compare your circulatory system to a busy street in a city or town.
    15·1 answer
  • The ___________________ of atoms determine how atoms will react with each other.
    15·1 answer
  • On Monday while Johnny was getting ready for school, he was in the bathroom holding his comb when he got an itch on his head. Jo
    9·2 answers
  • Calculate [H3O+] and [OH−] for each of the following solutions at 25 ∘C given the pH. pH= 8.74, pH= 11.38, pH= 2.81
    9·1 answer
  • 04 Question (1 point)
    10·1 answer
  • How do the hours of daylight change throughout the year in Reno, NV?
    11·1 answer
  • The Young's modulus values for iron and lead are 210 GPa and 16 GPa, respectively. Based on the information, which statement is
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!