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xenn [34]
2 years ago
13

A converging meniscus lens has an index of refraction of 1.55 and radii of curvature for its surfaces of 4.60 cm and 9.20 cm. Th

e concave surface is placed upward and filled with carbon tetrachloride (CCl4), which has n = 1.46. What is the focal length of the CCl4-glass combination?
Physics
1 answer:
SOVA2 [1]2 years ago
7 0

Answer: the focal length of the CCl4-glass combination is 102.31 cm

Explanation:

Given that;

Index of refraction n1 = 1.55

carbon tetrachloride (CCl4), which has n2 = 1.46

radii of curvature for its surfaces R1 = 4.6cm and R2 = 9.20 cm

the focal length of the CCl4-glass combination = ?

we can determine the focal length using the Formula;

1/f = ( n1 - n2) ( 1/R1 - 1/R)

so we substitute in our values

1/f = ( 1.55 - 1.46 ( 1/4.6 - 1/9.20)

1/f = 0.09 × 0.1086

1/f = 0.009774

f = 1 / 0.009774

f = 102.31 cm

Therefore the focal length of the CCl4-glass combination is 102.31 cm

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Answer:

The question is incomplete. However, I believe, it is asking for the acceleration of the elevator. This is 3.16 m/s².

Explanation:

By Hooke's law, F = ke

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From the question,

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F = ma

a = \dfrac{F}{m}

a = \dfrac{64.8 \text{ N}}{5\text{ kg}} = 12.96\text{ m/s}^2

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3 years ago
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Answer:

1.02 m/s²

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 0 m/s

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Acceleration can simply be defined as the change of velocity with time. Mathematically, it can be expressed as:

a = (v – u) / t

Where:

a is the acceleration.

v is the final velocity.

u is the initial velocity.

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With the above formula, we can obtain the acceleration of the car as follow:

Initial velocity (u) = 0 m/s

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a = (v – u) / t

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a = 6.6 / 6.5

a = 1.02 m/s²

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Answer:

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