Answer
given,
heat added to the gas,Q = 3300 kcal
initial volume, V₁ = 13.7 m³
final volume, V₂ = 19.7 m³
atmospheric pressure, P = 1.013 x 10⁵ Pa
a) Work done by the gas
W = P Δ V
W = 1.013 x 10⁵ x (19.7 - 13.7)
W = 6.029 x 10⁵ J
b) internal energy of the gas = ?
now,
change in internal energy
Δ U = Q - W
Q = 3300 x 10³ cal
Q = 3300 x 10³ x 4.186 J
Q = 1.38 x 10⁷ J
now,
Δ U = 1.38 x 10⁷ - 6.029 x 10⁵
Δ U = 1.32 x 10⁷ J
Answer:
Velocity
Explanation:
We finds that the winds are coming from the west at 15 miles per hour. This information shows the velocity of the wind. Since, velocity is a vector quantity. It has both magnitude and direction. 15 miles per hour shows the speed of wind and west shows the direction of wind motion.
Hence, the given information describes wind velocity.
Answer:
We know the information about atomic size, energy, electronic configuration etc. of atom from the periodic table.
Explanation:
- Periodic table is the arrangement of elements that are arranged according to their properties and electronic configuration.
- In periodic table, on furthest right side of the periodic table, noble gases like He, Ne, Ar etc are arranged.
- The atomic number of element increases while moving from left towards right in the periodic table.
- The metallic character of element decreases as we proceed the table towards right.
- They readily accept electron to fill the valence shell hence becoming more metallic in character.
Answer: W = 
J
Explanation: Since the potassium ion is at the outside membrane of a cell and the potential here is lower than the potential inside the cell, the transport will need work to happen.
The work to transport an ion from a lower potential side to a higher potential side is calculated by
q is charge;
ΔV is the potential difference;
Potassium ion has +1 charge, which means:
p = 
C
To determine work in joules, potential has to be in Volts, so:
Then, work is
To move a potassium ion from the exterior to the interior of the cell, it is required J of energy.
Explanation:
It is given that,
Mass of the woman, m₁ = 52 kg
Angular velocity, 
Mass of disk, m₂ = 118 kg
Radius of the disk, r = 3.9 m
The moment of inertia of woman which is standing at the rim of a large disk is :
I₁ = 790.92 kg-m²
The moment of inertia of of the disk about an axis through its center is given by :
I₂ =897.39 kg-m²
Total moment of inertia of the system is given by :
I = 1688.31 kg-m²
The angular momentum of the system is :
So, the total angular momentum of the system is 4980.5 kg-m²/s. Hence, this is the required solution.
