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4 years ago

What is nuclear energy

2 answers:

8 0

Nuclear Energy is : Energy released by reactions within atomic nuclei , as in Nuclear Fission and Nuclear Fusion

My reason being is because this is the outcome of some radio active plants when they release "gas" or chemicals into the air.

I hope this helps.

irina1246 [14]4 years ago

6 0

Nuclear energy is the energy released during nuclear fission or fusion.

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An oil droplet is levitated and held at rest in a region where the electric field is 1.4x104 N/C directed vertically downwards.

Ratling [72]

W = m g weight of drop

W = q E

m = q E / g = = 3 e E / g

m = 3 * 1.6E-19 * 1.4E4 / 9.8 = 6.96E-16 kg

8 0

3 years ago

Car wheel's slip in mud. why?

Lina20 [59]

Answer:

Because its wet

Explanation:

3 0

4 years ago

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If light and sound travel from point A to point B and start at the same time, which will reach point B first?

FinnZ [79.3K]

Light. Because we all should know that light travels faster than sound so light will get there first

5 0

4 years ago

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A wire 2.80 m in length carries a current of 5.20 A in a region where a uniform magnetic field has a magnitude of 0.430 T. Calcu

galina1969 [7]

Question:

A wire 2.80 m in length carries a current of 5.20 A in a region where a uniform magnetic field has a magnitude of 0.430 T. Calculate the magnitude of the magnetic force on the wire assuming the following angles between the magnetic field and the current.

(a)60 (b)90 (c)120

Answer:

(a)5.42 N (b)6.26 N (c)5.42 N

Explanation:

From the question

Length of wire (L) = 2.80 m

Current in wire (I) = 5.20 A

Magnetic field (B) = 0.430 T

Angle are different in each part.

The magnetic force is given by

$F=I \times B \times L \times sin(\theta)$

So from data

$F = 5.20 A \times 0.430 T \times 2.80 sin(\theta)\\\\F=6.2608 sin(\theta) N$

Now sub parts

(a)

$\theta=60^{o}\\\\Force = 6.2608 sin(60^{o}) N\\\\Force = 5.42 N$

(b)

$\theta=90^{o}\\\\Force = 6.2608 sin(90^{o}) N\\\\Force = 6.26 N$

(c)

$\theta=120^{o}\\\\Force = 6.2608 sin(120^{o}) N\\\\Force = 5.42 N$

3 0

3 years ago

Una masa de 0,5 kg está sobre una pendiente inclinada 20º sujeta mediante una cuerda paralela a la pendiente que impide que desl

jeka94

Answer:

4.61 N

Explanation:

masa = 0.5 kg

ángulo de inclinación = 20°

Peso normal de la masa = mg

donde m = masa

g = aceleración debido a la gravedad = 9.81 m/s^2

Peso normal = 0.5 x 9.81 = 4.905 N

Si la masa se mantiene en su lugar mediante una cuerda paralela al plano, y no hay fricción en la masa, entonces

La fuerza sobre la cuerda = peso normal x cos ∅

donde ∅ = 20 °

La fuerza sobre la cuerda = 4.905 x cos 20°

==> 4.61 N

4 0

3 years ago