Explanation:
Given:
v₀ = 22 m/s
v = 0 m/s
t = 17.32 s
Find: a
v = at + v₀
(0 m/s) = a (17.32 s) + (22 m/s)
a = -1.270 m/s²
Round as needed.
 
        
                    
             
        
        
        
 Answer:
a. A = 0.1656 m 
b. % E = 1.219 
Explanation:
Given 
mB = 4.0 kg , mb = 50.0 g = 0.05 kg , u₁ = 150  m/s , k = 500 N / m
a.
To find the amplitude of the resulting SHM using conserver energy 
ΔKe + ΔUg + ΔUs = 0 
¹/₂ * m * v²  -  ¹/₂ * k * A² = 0
A = √ mB * vₓ² / k 
vₓ = mb * u₁ / mb + mB 
vₓ = 0.05 kg * 150 m / s / [0.050 + 4.0 ] kg = 1.8518
A = √ 4.0 kg * (1.852 m/s)²   /   (500 N / m)
A = 0.1656 m 
b.
The percentage of kinetic energy 
%E = Es / Ek
Es = ¹/₂ * k * A² = 500 N / m * 0.1656²m = 13.72 N*0.5
Ek = ¹/₂ * mb * v² = 0.05 kg * 150² m/s = 1125 N 
% E = 13.72 / 1125 = 0.01219 *100
% E = 1.219 
 
        
             
        
        
        
Friction occurs when the surfaces and heat of two surfaces grind against each other.
I think these are the answers