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Snezhnost [94]
3 years ago
11

HELP ASAP PLEASE!!! 20 POINTS!!

Mathematics
1 answer:
Kobotan [32]3 years ago
6 0

Answer: S_{12}=399.90

Step-by-step explanation:

You know that the formula to find the sum of a finite geometric series is:

S_n=\frac{a_1(1-r^n)}{1-r}

Where n is the number of terms, a_1 is the first term and r is the common ratio (r\neq 1).

The steps to find the sum of the first 12 terms of the given geometric serie, are:

1. Find the common ratio "r". By definition:

r=\frac{a_2}{a_1}

Then:

r=\frac{100}{200}\\\\r=\frac{1}{2}

2. Finally, knowing that:

a_1=200\\\\n=12

You must substitute values into the formula.

Then you get:

S_{12}=\frac{200(1-(\frac{1}{2})^{12})}{1-\frac{1}{2}}\\\\S_{12}=399.90

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What is the remainder of f(x)=x^4-2x^3-27x^2-9x+18 when divided by binomial x+4
givi [52]

Answer:

The remainder will be 6.

Step-by-step explanation:

We have the function:

f(x)=x^4-2x^3-27x^2-9x+18

And we want to find the remainder after it is divided by the binomial:

x+4

We can use the Polynomial Remainder Theorem. According to the PRT, if we have a polynomial P(x) being divided by a binomial in the form (<em>x</em> - <em>a</em>), then the remainder will be given by P(a).

Here, our divisor is (<em>x</em> + 4). We can rewrite this as (<em>x</em> - (-4)).

Therefore, <em>a</em> = -4.

Then according to the PRT, the remainder will be:

f(-4)=(-4)^4-2(-4)^3-27(-4)^2-9(-4)+18=6

The remainder will be 6.

4 0
3 years ago
AM is a median in △ABC (M∈ BC ). A line drawn through point M intersects AB at its midpoint P. Find areas of △APC and △PMC, if A
Snowcat [4.5K]

Answer:

The area of APC is 70m². The area of triangle PMC is 35m².

Step-by-step explanation:

Let the area of triangle ABC be x.

It is given that AM is median, it means AM divides the area of triangle in two equal parts.

\text{Area of }\triangle ACM=\text{Area of }\triangle ABM=\frac{x}{2}    .....(1)

The point P is the midpoint of AB, therefore the area of APC and BPC are equal.

\text{Area of }\triangle APC=\text{Area of }\triangle BPC=\frac{x}{2}          ......(2)

The point P is midpoint of AB therefore the line PM divide the area of triangle ABM in two equal parts. The area of triangle APM and BPM are equal.

\text{Area of }\triangle APM=\text{Area of }\triangle BPM=\frac{x}{4}        .....(3)

The area of triangle APM is 35m².

\text{Area of }\triangle APM=\frac{x}{4}

35=\frac{x}{4}

x=140

Therefore the area of triangle ABC is 140m².

Using equation (2).

\text{Area of }\triangle APC=\frac{x}{2}

\text{Area of }\triangle APC=\frac{140}{2}

\text{Area of }\triangle APC=70

Therefore the area of triangle APC is 70m².

Using equation (3), we can say that the area of triangle BPM is 35m² and by using equation (2), we can say that the area of triangle BPC is 70m².

\triangle BPC=\triangle BPM+\triangle PMC

70=35+\triangle PMC

35=\triangle PMC

Therefore the area of triangle PMC is 35m².

8 0
3 years ago
What is the height of the trapezoid ? A) 3units B) 5units C) 10units D) 12units
zheka24 [161]

Answer:

b) 5

Step-by-step explanation:

6+10=16

40 times 2 = 80

80 div by 15 = 5

5 0
3 years ago
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5 1<br> - - - = <br> 8 3<br><br> simplify the expression
tensa zangetsu [6.8K]
The answer is...
7
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24
8 0
3 years ago
Hi if y’all would like to help I would rlly appreciate it :) also +30 points if u can help meeeee thanks!
Vika [28.1K]

Answer:

a) X=0

b) X=2,-2

Step-by-step explanation:

7 0
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