GiveN:
- Initial velocity = 9.8 m/s²
- Accleration due to gravity = -9.8 m/s²
- Time taken = 1 s
To FinD:
- Final velocity of the ball?
Step-by-step Explanation:
Using the first Equation of motion,
⇒ v = u + gt
⇒ v = 9.8 + -9.8(1)
⇒ v = 0 m/s
The final velocity is hence <u>0</u><u> </u><u>m</u><u>/</u><u>s</u><u>.</u>
<h3>
Note:</h3>
- While solving questions of under gravity motions using equations of motion, remember the sign convection to avoid mistakes.
- You can consider positive above the ground and negative for towards it.
Answer:
Explanation:
Acceleration is defined as the change in velocity per unit of time
Acceleration (a) = ΔV/t
V = Velocity t = time
ΔV = V₂ - V₁ t = 11s
V₁ = 44m/s
V₂ = 66m/s
ΔV = 66 - 44
= 22m/s
Acceleration (a) = 22/11
= 2m/s²
Displacement (d): Displacement equals the original velocity multiplied by time plus one half the acceleration multiplied by the square of time.
d = v₀ + 1/2*at²
v₀ = 44m/s
a = 2m/s
t = 11s
d = 44 + 1/2*(2 x 11²)
= 44 + 121
d = 165m
The mass of the seashell suspended by the two strands of spider silk is 0.28 kg.
The given parameters:
- <em>Tension on each strand of silk, T = 1.42 N</em>
- <em>Angle of inclination of each strand, θ = 75⁰</em>
The mass of the seashell at equilibrium is calculated by applying Newton's second law of motion;
where;
- W is the weight of the seashell
The weight of the seashell is calculated as;
The mass of the seashell is calculated as follows;
Thus, the mass of the seashell suspended by the two strands of spider silk is 0.28 kg.
Learn more about equilibrium forces here: brainly.com/question/8045102
Laurentia, also called the North American Craton, is a huge continental craton. It<span> forms the ancient </span>geological<span> core of the </span>continent of North America.<span> It is made up of present day North America and Greenland. About 300 million years ago, it collided with the southern hemispheric continent of </span>Gondwana<span> and formed the supercontinent called Pangaea.</span><span> </span>
Answer: 1.044 E -17 A
Explanation:
L =1.50m
A = 0.380mm = 3.8E- 7
Resistivity p =1.70 E-8
R =pl/A
R = 1.70 E-8 × 1.5/ 3.8 E-7
R = 6.71 E-16 ohms
V = IR
0.700 = I × 6.71 E-16
I =1.044E-17 A