<h2>Answer:</h2><h3>D. ability to react with oxygen</h3><h2>Explanation:</h2>
<em>Im</em><em> </em><em>not</em><em> </em><em>sure</em><em> </em><em>this</em><em> </em><em>in</em><em> </em><em>your</em><em> </em><em> </em><em>choices</em><em> </em><em>but</em><em> </em><em>if</em><em> </em><em>it</em><em> </em><em>is</em><em>,</em><em> </em><em>this</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>answer</em><em>. </em>
<em>I</em><em> </em><em>hope</em><em> </em><em>I've</em><em> </em><em>helped</em><em>. </em>
The second option is the correct one. m/s^2
Answer:
v = 6i + 12j + 4k
Explanation:
Find the magnitude of the direction vector.
√(3² + 6² + 2²) = 7
Normalize the direction vector.
3/7 i + 6/7 j + 2/7 k
Multiply by the magnitude of v.
v = 14 (3/7 i + 6/7 j + 2/7 k)
v = 6i + 12j + 4k
<h2>Answers:</h2><h2 /><h2>a) Arrow B</h2><h2>b) Arrow E</h2>
Explanation:
Refraction is a phenomenon in which a wave (the light in this case) bends or changes its direction <u>when passing through a medium with a refractive index different from the other medium.</u> Where the Refractive index is a number that describes how fast light propagates through a medium or material.
According to this, if we observe the rays A an D passing throgh the biconcave lens, we will have two mediums:
1) The air
2)The material of the biconcave lens
This two mediums have different refractive indexes, hence the rays will change the direction.
-For the incident ray A, the corresponding refractive ray is B, because is the ray that bends after passing throgh the lens
-For the incident ray D, the refracted ray is E following the same principle.