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nikdorinn [45]
3 years ago
15

Need help finding the answer for this one if you know it please help

Mathematics
1 answer:
Dahasolnce [82]3 years ago
5 0
Just move the negative in front of the fraction !
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56 books 75% increase
Sliva [168]
56 * .75 = 42
42+ 56 = 98
Answer is 98
6 0
3 years ago
2 * 10^-4 - 1 * 10^-5<br><br> Show your work.
gladu [14]
<span>2 * 10^-4 - 1 * 10^-5
= 10^-4 ( 2 - 1 * 10^-1)
= 10^-4 ( 2 - 0.1)
= 10^-4 (1.9)
= 1.9 * 10^-4

hope it helps</span>
7 0
3 years ago
Find the number of elements in A 1 ∪ A 2 ∪ A 3 if there are 200 elements in A 1 , 1000 in A 2 , and 5, 000 in A 3 if (a) A 1 ⊆ A
lina2011 [118]

Answer:

a. 4600

b. 6200

c. 6193

Step-by-step explanation:

Let n(A) the number of elements in A.

Remember, the number of elements in A_1 \cup A_2 \cup A_3 satisfies

n(A_1 \cup A_2 \cup A_3)=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)

Then,

a) If A_1\subseteq A_2, n(A_1 \cap A_2)=n(A_1)=200, and if A_2\subseteq A_3, n(A_2\cap A_3)=n(A_2)=1000

Since A_1\subseteq A_2\; and \; A_2\subseteq A_3, \; then \; A_1\cap A_2 \cap A_3= A_1

So

n(A_1 \cup A_2 \cup A_3)=\\=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\=200+1000+5000-200-200-1000-200=4600

b) Since the sets are pairwise disjoint

n(A_1 \cup A_2 \cup A_3)=\\n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\200+1000+5000-0-0-0-0=6200

c) Since there are two elements in common to each pair of sets and one element in all three sets, then

n(A_1 \cup A_2 \cup A_3)=\\=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\=200+1000+5000-2-2-2-1=6193

8 0
3 years ago
Tell whether the system has one solution infinitely many solutions or no solution <br> x=-7y+34
marin [14]
Add -7y and divide both sides to get one solution (0.20588)
5 0
3 years ago
Explain how finding 4 times 384 can help you find 4 times 5,384
Mumz [18]
Well, 5384 is 5000 bigger than 384. So you would add 20000 (4*5000) to the answer of 4*384, which is 1536.
So 1536+20000=21536
4 0
4 years ago
Read 2 more answers
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