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Sebastian has $3.75 worth of dimes and quarters. He has a total of 21 dimes and quarters altogether. Determine the number of dim

Nostrana [21]

Answer:

Sebastian cold have 10 dimes and 11 quarters.

Step-by-step explanation:

11 quarters = $2.75

10 dimes = $1.00

6 0

2 years ago

L=a+(n-1)d <br><br> solve for n

earnstyle [38]

Answer:

(L-a)/d + 1 = n

Step-by-step explanation:

Let's isolate (n-1), and after that isolate n:

1) subtract a from both sides: L - a = (n-1)d

2) Divide both sides by d: (L-a)/d = n-1

3) Add 1 to both sides, to isolate n: (L-a)/d + 1 = n

3 0

2 years ago

Radio signals travel at a rate of 3 x 10^8 meters per second. How many seconds would it take for a radio signal to travel from a

wel

Time = Distance / Speed [ Already mentioned ]

Then, substitute the known values,

t = (9.6 × 10⁶) / (3 × 10⁸)

t = 3.2 × 10⁻² s

In short, Your Answer would be Option B

Hope this helps!

4 0

2 years ago

An admiral, captain, and commander, all different, are to be chosen from a group of 10 Starfleet officers. How many different ch

zepelin [54]

Answer:

$10C1 *9C1*8C1 = 10*9*8=720$

Step-by-step explanation:

For this case in order to select the one admiral, captain and commander, all different. We are assuming that the order in the selection no matter, so we can begin selecting an admiral then a captain and then a commander.

So we have 10C1 ways to select one admiral since we want just one

Now we have remaining 9 people and we have 9C1 ways to select a captain since we want a captain different from the admiral selected first

Now we have remaining 8 people and we have 8C1 ways to select a commander since we want a commander different from the captain selected secondly.

The term nCx (combinatory) is defined as:

$nCx = \frac{n!}{x! (n-x)!}$

And by properties $nC1= n$

So then the number of possible way are:

$10C1 *9C1*8C1 = 10*9*8=720$

If we select first the captain then the commander and finally the admiral we have tha same way of select $10*9*8=720$

For all the possible selection orders always we will see that we have 720 to select.

5 0

2 years ago

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A simple random sample of 60 items resulted in a sample mean of 65. The population standard deviation is 14. a. Compute the 95%

bazaltina [42]

Answer:

The 95% confidence interval for the population mean is between 61.5 and 68.5.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.96*\frac{14}{\sqrt{60}} = 3.5$

The lower end of the interval is the sample mean subtracted by M. So it is 65 - 3.5 = 61.5

The upper end of the interval is the sample mean added to M. So it is 65 + 3.5 = 68.5

The 95% confidence interval for the population mean is between 61.5 and 68.5.

6 0

2 years ago

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