Answer : The molality of NaCl is, 1.95 mol/kg
Explanation :
Formula used for Elevation in boiling point :
where,
= change in boiling point =
= boiling point constant for water =
m = molality
i = Van't Hoff factor = 2 (for electrolyte)
The dissociation will be,
So, Van't Hoff factor = Number of solute particles = = 1 + 1 = 2
Now put all the given values in the above formula, we get:
Therefore, the molality of NaCl is, 1.95 mol/kg
Answer: Amount of sodium chloride produced is 25.43 grams.
Explanation:
To calculate the moles:
Given: Mass of sodium = 10 g
Molar mass of sodium = 23g/mol
The balanced equation is:
By Stoichiometry of the reaction,
2 moles of sodium produces 2 moles of sodium chloride
So, 0.4347 moles of sodium will produce = of sodium chloride.
Molar mass of sodium chloride = 58.5 g/mol
Putting values in equation 1, we get:
Hence, amount of sodium chloride produced is 25.43 grams.