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Gemiola [76]
4 years ago
15

The following median grain size data were obtained during isothermal liquid phase sintering of an 82W-8Mo-8Ni-2Fe alloy. What is

the time dependence for the grain growth in the system and what is the probable grain-coarsening mechanism?Ignore the initial grain size. Time, min 30 120 480 960 grain size, um 6.0 13.4 21.3 31.6

Engineering
1 answer:
Morgarella [4.7K]4 years ago
8 0

Answer:

The probable grain-coarsening mechanism is : Ideal grain growth mechanism

( d^{2}- d_{0} ^{2} = kt )

Explanation:

The plot attached below shows the time dependence of the growth of grain.

The probable grain-coarsening mechanism is : Ideal grain growth mechanism

the ideal growth follows this principle = d^{2} - d^{2} _{0}  = kt

d = final grain size

d_{0} = initial grain size

k = constant ( temperature dependent )

t = 0

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Why Elastic Modulus is important and on what it depends?
Bad White [126]

Answer:

The Young's Modulus of a material is a fundamental property of every material that cannot be changed. It is dependent upon temperature and pressure however. The Young's Modulus (or Elastic Modulus) is in essence the stiffness of a material. In other words, it is how easily it is bended or stretched.

Explanation:

Have a great day

5 0
3 years ago
Serratia marcescens bacteria are used for the production of threonine. The maximum specific oxygen uptake rate of S. marcescens
Sati [7]

Answer:

The rate of cell metabolism is limited by mass transfer since the value of maximum cell concentration obtained (38 g/l) is lower than 50 g l-1, the value planed.

Explanation:

                                                     Data

<u>kLa</u> = 0.17/s

<u>Solubility of oxygen</u> =  8 × 10^-3 kg / m^3

<u>The maximum specific oxygen uptake rate </u>= 4 mmol O2 / g h.

<u>Concentration of oxygen</u> =  0.5 × 10^-3 kg/ m^3

<u>**The maximum cell density</u> = 50 g/l

___________________

The calculated maximum cell concentration:

xmax=  kLa · CAL*/ qo

CAL* is the solubility of oxygen in the broth and qo is the specific oxygen uptake rate

Replacing the data given

xmax= ( 0.17/s ) ·   (8 × 10^-3 kg / m^3)  /  4 mmol O2 / g h

4 mmol O2 / g h  to kg O2/ g s

4 \frac{mmol}{gh} \frac{1 gmol}{1000mmol}\frac{1h}{3600s}\frac{32 g}{gmol} \frac{1Kg}{1000g}

= 3.56 x 10^-3 kg O2/ g s

So then,

xmax= ( 0.17/s ) ·   (8 × 10^-3 kg / m^3)  / 3.56 x 10^-3 o kg O2/ g s

xmax= 3. 8 x 10^4 g/ m^3   = 38 g/l

_____________________

5 0
3 years ago
What phase of the moon would someone
Leni [432]

Answer:

Explanation:

exactly through the other side of the moon

6 0
2 years ago
g Write a program that takes in a positive integer as input, and outputs a string of 1's and 0's representing the integer in bin
Phoenix [80]

Answer:

The solution is written in Python

  1. binary = ""
  2. decimal = 13
  3. quotient = int(decimal / 2)  
  4. remainder = decimal % 2
  5. binary = str(remainder) + binary
  6. while(quotient >0):
  7.    decimal = int(decimal / 2)
  8.    quotient = int(decimal / 2)  
  9.    remainder = decimal % 2
  10.    binary = str(remainder) + binary
  11. print(binary)

Explanation:

Firstly, we declare a variable <em>binary</em> and initialize it with an empty string (Line 1). This <em>binary </em>is to hold the binary string.

Next, we declare variable <em>decimal, quotient </em>and<em> remainder </em>(Line 2-4). We assign a test value 13 to decimal variable and then get the first quotient by dividing decimal with 2 (Line 3). Then we get the remainder by using modulus operator, % (Line 4). The first remainder will be the first digit joined with the binary string (Line 5).  

We need to repeat the process from Line 3-5 to get the following binary digits. Therefore create a while loop (Line 7) and set a condition that if quotient is bigger than 0 we keep dividing decimal by 2 and calculate the quotient and remainder and use the remainder as a binary digit and join it with binary string from the front (Line 9-11).

At last, we print the binary to terminal (Line 13).

4 0
4 years ago
A​ special-purpose 30-horsepower electric motor has an efficiency of 9090​%. Its purchase and installation price is ​$2 comma 20
Taya2010 [7]

Answer:

Motor 1 recommended  

Given Information:

Two 30-horsepower motors

Consumption = 4,000 hours per year

Electricity cost = ​$0.10 per​ kWh

Load factor of motors = 60​%

MARR = 15​%

Study period = 8 years

Motor 1:

Efficiency = 90​%

Purchase + Installation cost = $2,200

Motor 2:

Efficiency = 93%

Purchase + Installation cost = $3,200

Required information:

Which motor should be recommended under these conditions = ?

Solution:

Electricity cost = Rate of electricity*Units consumed*Load factor

Electricity cost: Motor 1

Units consumed = (30 hp/0.90)*(0.746 kW/hp)*(4000 h/year)

Units consumed = 99,466.66 kWh/year

Electricity cost = (99,466.66 kWh/year)*(0.10/kWh)*(0.60)

Electricity cost = $5,968 per year

Electricity cost: Motor 2

Units consumed = (30 hp/0.93)*(0.746 kW/hp)*(4000 h/year)

Units consumed = 96,258 kWh/year

Electricity cost = (96,258 kWh/year)*(0.10/kWh)*(0.60)

Electricity cost = $5,775 per year

Present Worth Analysis: Motor 1

PW = -$2,200 - $5,968( P/A, 15%, 8)

where (P/A,15%,8) = Uniform series present worth at 15% MARR and n = 8 years

P/A = (1 + i)ⁿ - 1/ i*(1 + i)ⁿ

P/A = (1 +0.15)ⁿ - 1/ 0.15(1 + 0.15)ⁿ

P/A = 4.487

PW = -$2,200 - $5,968(4.487)

PW = -$28,978

Present Worth Analysis: Motor 2

PW = -$3,200 - $5,775( P/A, 15%, 8)

P/A = 4.487

PW = -$3,200 - $5,775(4.487)

PW = -$29,112

Recommendation:

In present worth analysis, we select the alternative which has largest PW value i.e more positive or least negative.

Since the PW of motor 1 (90% efficiency) is greater (less negative) than the motor 2 (93% efficiency).

Therefore, Motor 1 recommended  

4 0
4 years ago
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