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Lelechka [254]
3 years ago
7

Explain what we mean by the statement density of a substance is one gcm^3​

Physics
1 answer:
professor190 [17]3 years ago
8 0

Answer:

The gram per cubic centimeter is a unit of density in the CGS system.

The official SI symbols are g/cm^3 , g. cm^-3.

It is equivalent to the units (g/mL) & (Kg/L).

<h3>Hope it helps! </h3>
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Who was the scientist who gave us the laws of motion?.
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Answer:

Isaac Newton

Explanation:

Newton's laws of motion, three statements describing the relations between the forces acting on a body and the motion of the body.

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Which statement best describes the energy changes that occur while a child is riding on a sled down a steep, snow-covered hill?
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B. kinetic energy increases and potential energy decreases
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A bullet is fired straight up from a gun with a
melamori03 [73]

Answer: 815.51 m

Explanation:

This situation is related to projectile motion or parabolic motion, in which the initial velocity of the bullet has only y-component, since it was fired straight up. In addition, we are dealing with constant acceleration (due gravity), therefore the following equations will be useful to solve this problem:

V=V_{o}+gt (1)

V^{2}=V_{o}^{2}+2gy (2)

Where:

V is the final velocity of the bullet

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g=-9.8 m/s^{2} is the acceleration due gravity, always directed downwards

t=6.9 s is the time

y is the vertical position of the bullet at t=6.9 s

Let's begin by finding V from (1):

V=152 m/s-9.8 m/s^{2}(6.9 s) (3)

V=84.38 m/s (4)

Now we have to substitute (4) in (2):

(84.38 m/s)^{2}=(152 m/s)^{2}-2(9.8 m/s^{2})y (5)

Isolating y:

y=815.511 m This is the displacement  of the bullet after 6.9 s

8 0
3 years ago
Unpolarizedlight of intensity I_0 is incident on three polarizingfilters. The axis of the first is vertical, that of the secondi
Marina86 [1]

To solve this problem it is necessary to apply the concepts related to the law of Malus which describe the intensity of light passing through a polarizer. Mathematically this law can be described as:

I = I_0 cos^2\theta

Where,

I_0 = Indicates the intensity of the light before passing through the polarizer

I = Resulting intensity

\theta= Indicates the angle between the axis of the analyzer and the polarization axis of the incident light

From the law of Malus when the light passes at a vertical angle through the first polarizer its intensity is reduced by half therefore

I_1= \frac{I_0}{2}

In the case of the second polarizer the angle is directly 60 degrees therefore

I_2 = I_1 cos^2\theta

I_2 = (\frac{I_0}{2} ) cos^2(60)

I_2 = 0.125I_0

In the case of the third polarizer, the angle is reflected on the perpendicular, therefore, its angle of index would be

\theta_3 = 90-60 = 30

Then,

I_3 = I_2 cos^2\theta_3

I_3 = 0.125I_0 cos^2 (30)

I_3 = 0.09375I_0

Then the intensity at the end of the polarized lenses will be equivalent to 0.09375 of the initial intensity.

5 0
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