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2 years ago

14

A body found with rigor throughout the body

1 answer:

-BARSIC- [3]2 years ago

7 0

Answer:

Can you move a body in rigor mortis?

Rigor mortis -- the lay version of it is stiffening of the joints. It really had nothing to do with the joints. It's the lack of chemical in the body, ATP, which is Adenosine Triphosphate. It goes away and you can now move the extremities easily after rigor mortis is gone away.

Explanation:

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What mass of mgo is produced from 2.00 moles of mg ? Mg +02 mgo

Vanyuwa [196]

Chemical Reactions and Moles of Reactants and Products
That is, it requires 2 moles of magnesium and 1 mole of oxygen to produce 2 moles of magnesium oxide. If only 1 mole of magnesium was present, it would require 1 ÷ 2 = ½ mole of oxygen gas to produce 2 ÷ 2 = 1 mole magnesium oxide.

3 0

3 years ago

What would happen to the moon’s interia were to increase? A the moon will fly into space. B the moon will smash into Earth. C th

Montano1993 [528]

Answer:

B

Explanation:

5 0

2 years ago

A solution has a [H3O+] of 1x 10-5 M. What is the [OH-] of the solution? (5 points)

White raven [17]

Answer:

1x10^–9 M

Explanation:

From the question given,

Concentration of hydronium ion, [H3O+] = 1x10^-5 M.

Concentration of Hydroxide ion, [OH-] =..?

The concentration of the hydroxide ion, [OH-] can be obtained as follow:

[H3O+] x [OH-] = 1x10^–14

1x10^-5 M x [OH-] = 1x10^–14

Divide both side by 1x10^-5

[OH-] = 1x10^–14 / 1x10^-5

[OH-] = 1x10^–9 M

8 0

3 years ago

Calculate the volume in liters of a 0.00231M copper(II) fluoride solution that contains 175.g of copper(II) fluoride CuF2. Be su

Free_Kalibri [48]

Answer:

Volume = 746 L

Explanation:

Given that:- Mass of copper(II) fluoride = 175 g

Molar mass of copper(II) fluoride = 101.543 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{175\ g}{101.543\ g/mol}$

$Moles_{copper(II)\ fluoride}= 1.7234\ mol$

Also,

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

So,,

$Volume =\frac{Moles\ of\ solute}{Molarity}$

Given, Molarity = 0.00231 M

So,

$Volume =\frac{1.7234}{0.00231}\ L$

<u>Volume = 746 L</u>

7 0

2 years ago

Consider the following equilibrium: CO2(g) + C(graphite) 2CO(g); ΔH = 172.5 kJ The equilibrium constant for this reaction will

bezimeni [28]

Answer: Option (B) is the correct answer.

Explanation:

As the given reaction is as follows.

$CO_{2}(g) + C(graphite) \rightarrow 2CO(g)$

Equilibrium constant for this reaction will be as follows.

$K_{c} = \frac{[CO_{2}]}{[CO]^{2}}$

According to Le Chatelier's principle, when we increase the temperature then the equilibrium will shift towards the right hand side.

As a result, concentration of carbon dioxide will decrease whereas concentration of carbon monoxide will increase.

Thus, we can conclude that in the given reaction equilibrium constant for this reaction will decrease with increasing temperature.

8 0

3 years ago