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anyanavicka [17]
3 years ago
6

A race car travels on a circular track at an average rate of 125 mi/h. The radius of the track is 0.320 miles. What is the centr

ipetal acceleration of the car?
Chemistry
2 answers:
IRISSAK [1]3 years ago
4 0
<h3><u>Answer;</u></h3>

<em><u> = 48,828.125 mi/hr²</u></em>

<h3><u>Explanation and solution</u>;</h3>
  • <em><u>Centripetal acceleration is the rate of change of angular velocity. Centripetal acceleration occurs towards the center of the circular path along the radius of the circular path</u></em>.
  • Centripetal acceleration is given by; <em>V²/r ; </em>

<em>V = 125 mi/h and r = 0.320 miles </em>

  • <em>Thus; centripetal acceleration = 125²/0.320 </em>

                                                  =15625/0.320

                                                 <em><u> = 48,828.125 mi/hr²</u></em>

allsm [11]3 years ago
4 0
The centripetal acceleration is obtained from the quotient of the square of velocity and the radius. Hence, a= \frac{ v^{2} }{r}. Substituting the give, v=125 mi/h and r=0.320 mi, the answer is equal to 48,828.125 mi/hr^{2}.
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