1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
irina1246 [14]
3 years ago
6

Obtain the valence shell configuration of Al and S from their positions in the periodic table.

Chemistry
1 answer:
lutik1710 [3]3 years ago
3 0

Answer:

Al: 3

S: 6

Explanation:

Al is in Group III. This means that it has 3 valence electrons.

S is in Group VI. This means that it has 6 valence electrons.

I hope this helps :)

You might be interested in
What is the mass of 0.28 mol of iron
maria [59]
Mass = number of mol x molar mass
Mass = 0.28mol x 55.8g/mol
Mass = 15.624g
5 0
3 years ago
Read 2 more answers
What is the molar out of a solution that contains 33.5g of CaCl2 in 600.0mL of water
omeli [17]

Answer:

Here's what I got.

Explanation:

Interestingly enough, I'm not getting

0.0341% w/v

either. Here's why.

Start by calculating the percent composition of chlorine,

Cl

, in calcium chloride, This will help you calculate the mass of chloride anions,

Cl

−

, present in your sample.

To do that, use the molar mass of calcium chloride, the molar mass of elemental chlorine, and the fact that

1

mole of calcium chloride contains

2

moles of chlorine atoms.

2

×

35.453

g mol

−

1

110.98

g mol

−

1

⋅

100

%

=

63.89% Cl

This means that for every

100 g

of calcium chloride, you get

63.89 g

of chlorine.

As you know, the mass of an ion is approximately equal to the mass of the neutral atom, so you can say that for every

100 g

of calcium chloride, you get

63.89 g

of chloride anions,

Cl

−

.

This implies that your sample contains

0.543

g CaCl

2

⋅

63.89 g Cl

−

100

g CaCl

2

=

0.3469 g Cl

−

Now, in order to find the mass by volume percent concentration of chloride anions in the resulting solution, you must determine the mass of chloride anions present in

100 mL

of this solution.

Since you know that

500 mL

of solution contain

0.3469 g

of chloride anions, you can say that

100 mL

of solution will contain

100

mL solution

⋅

0.3469 g Cl

−

500

mL solution

=

0.06938 g Cl

−

Therefore, you can say that the mass by volume percent concentration of chloride anions will be

% m/v = 0.069% Cl

−

−−−−−−−−−−−−−−−−−−−

I'll leave the answer rounded to two sig figs, but keep in mind that you have one significant figure for the volume of the solution.

.

ALTERNATIVE APPROACH

Alternatively, you can start by calculating the number of moles of calcium chloride present in your sample

0.543

g

⋅

1 mole CaCl

2

110.98

g

=

0.004893 moles CaCl

2

To find the molarity of this solution, calculate the number of moles of calcium chloride present in

1 L

=

10

3

mL

of solution by using the fact that you have

0.004893

moles present in

500 mL

of solution.

10

3

mL solution

⋅

0.004893 moles CaCl

2

500

mL solution

=

0.009786 moles CaCl

2

You can thus say your solution has

[

CaCl

2

]

=

0.009786 mol L

−

1

Since every mole of calcium chloride delivers

2

moles of chloride anions to the solution, you can say that you have

[

Cl

−

]

=

2

⋅

0.009786 mol L

−

1

[

Cl

−

]

=

0.01957 mol L

−

This implies that

100 mL

of this solution will contain

100

mL solution

⋅

0.01957 moles Cl

−

10

3

mL solution

=

0.001957 moles Cl

−

Finally, to convert this to grams, use the molar mass of elemental chlorine

0.001957

moles Cl

−

⋅

35.453 g

1

mole Cl

−

=

0.06938 g Cl

−

Once again, you have

% m/v = 0.069% Cl

−

−−−−−−−−−−−−−−−−−−−

In reference to the explanation you provided, you have

0.341 g L

−

1

=

0.0341 g/100 mL

=

0.0341% m/v

because you have

1 L

=

10

3

mL

.

However, this solution does not contain

0.341 g

of chloride anions in

1 L

. Using

[

Cl

−

]

=

0.01957 mol L

−

1

you have

n

=

c

⋅

V

so

n

=

0.01957 mol

⋅

10

−

3

mL

−

1

⋅

500

mL

n

=

0.009785 moles

This is how many moles of chloride anions you have in

500 mL

of solution. Consequently,

100 mL

of solution will contain

100

mL solution

⋅

0.009785 moles Cl

−

500

mL solution

=

0.001957 moles Cl

−

So once again, you have

0.06938 g

of chloride anions in

100 mL

of solution, the equivalent of

0.069% m/v

.

Explanation:

i think this is it

8 0
3 years ago
How does most ocean water return to the ocean in the water cycle?
serious [3.7K]

Explanation:

The correct answer is C.

Through runoff on Earth's surface. Hope this helped!

3 0
2 years ago
Read 2 more answers
Enter the correct 4 digit code (no spaces)
Airida [17]
3618 is the numbers for the graph
3 0
3 years ago
Which is a NOT a freshwater source on Earth?
cluponka [151]

Answer:

B the atmosphere it's not on earth and I'm pretty sure  the atmosphere doesn't have water in

Explanation:

7 0
2 years ago
Other questions:
  • What types of compounds do not dissolve in water?
    13·1 answer
  • Name 20 inorganic compounds
    6·1 answer
  • Two types of heterogeneous mixtures are suspensions and colloids.<br>true or false<br><br>​
    15·1 answer
  • A mixture of nitrogen and hydrogen gases, at a temperature of 500
    10·1 answer
  • The type of radioactive particle that can be stopped by a sheet of paper is the
    14·1 answer
  • Within a plant, photosynthesis is critical. It provides cells with the glucose they need for
    8·2 answers
  • For fun<br><br> need full details to win<br> would you rather be a man or a women and why
    5·2 answers
  • In an experiment trying to dissolve sugar in water, a person boils water in a pot on the stove and then puts the water and the s
    8·1 answer
  • What product is obtained from the reaction of sulfuric acid acetic acid and 1 pentanol.
    9·1 answer
  • In one to two sentences, explain why metal is often used for making wire and the properties that make metal useful. (Will give 1
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!