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Dimas [21]
3 years ago
12

I need help with this ASAP!! someone

Mathematics
2 answers:
shepuryov [24]3 years ago
7 0

Answer:

490.56

Step-by-step explanation:

2 pi x radius squared + 2 pi x radius  x height

2 pi= 6.28 x 36= 226.80

2 pi = 6.28 x 6 x 7 = 263.78

Furkat [3]3 years ago
3 0

Answer:

791.28 cubic feet

Step-by-step explanation:

3.14*6²=113.04

113.04 is the area of the top, sop now we need to multiply it by 7, to get the volume.

113.04*7=791.28

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A serving of chickpeas contains 2,150 milligrams of potassium. How many grams of
Zepler [3.9K]

Answer: 109 mg

Step-by-step explanation:

5 0
3 years ago
A football stadium has 2,500 seats. For the first game of the season, 2,075 seats were filled. Which percent of seats were fille
malfutka [58]
83 % of the seats

2075 / 2500 x 100
5 0
3 years ago
Read 2 more answers
Write as a mathematical equation. The product of 5 and x is 25.
pickupchik [31]

answer:

5x=25

Divide 5 from both sides

5x/5=25/5

x=5

4 0
3 years ago
Calculating the degrees of freedom, the sample variance, and the estimated standard error for evaluations using the t statistic
Yuliya22 [10]

Answer:

a) For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

df = n-1= 10-1=9

d.9

b) s^2 = \frac{SS}{n-1}= \frac{600}{41-1}= 15

a.15

c) For this case we have the sample size n = 25 and the sample variance is s^2 =400 , the standard error can founded with this formula:

SE = \frac{s^2}{\sqrt{n}}= \frac{400}{\sqrt{25}}= 80

Step-by-step explanation:

Part a

For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

df = n-1= 10-1=9

d.9

Part b

From a sample we know that n=41 and SS= 600, where SS represent the sum of quares given by:

SS = \sum_{i=1}^n (X_i -\bar X)^2

And the sample variance for this case can be calculated from this formula:

s^2 = \frac{SS}{n-1}= \frac{600}{41-1}= 15

a.15

Part c

For this case we have the sample size n = 25 and the sample variance is s^2 =400 , the standard error can founded with this formula:

SE = \frac{s^2}{\sqrt{n}}= \frac{400}{\sqrt{25}}= 80

8 0
3 years ago
In a certain assembly plant, three machines B1, B2, and B3, make 30%, 20%, and 50%, respectively. It is known from past experien
diamong [38]

Answer:

The probability that a randomly selected non-defective product is produced by machine B1 is 11.38%.

Step-by-step explanation:

Using Bayes' Theorem

P(A|B) = \frac{P(B|A)P(A)}{P(B)} = \frac{P(B|A)P(A)}{P(B|A)P(A) + P(B|a)P(a)}

where

P(B|A) is probability of event B given event A

P(B|a) is probability of event B not given event A  

and P(A), P(B), and P(a) are the probabilities of events A,B, and event A not happening respectively.

For this problem,

Let P(B1) = Probability of machine B1 = 0.3

P(B2) = Probability of machine B2 = 0.2

P(B3) = Probability of machine B3 = 0.5

Let P(D) = Probability of a defective product

P(N) = Probability of a Non-defective product

P(D|B1) be probability of a defective product produced by machine 1 = 0.3 x 0.01 = 0.003

P(D|B2) be probability of a defective product produced by machine 2 = 0.2 x 0.03 = 0.006

P(D|B3) be probability of a defective product produced by machine 3 = 0.5 x 0.02 = 0.010

Likewise,

P(N|B1) be probability of a non-defective product produced by machine 1 = 1 - P(D|B1) = 1 - 0.003 = 0.997

P(N|B2) be probability of a non-defective product produced by machine 2  = 1 - P(D|B2) = 1 - 0.006 = 0.994

P(N|B3) be probability of a non-defective product produced by machine 3 = 1 - P(D|B3) = 1 - 0.010 = 0.990

For the probability of a finished product produced by machine B1 given it's non-defective; represented by P(B1|N)

P(B1|N) =\frac{P(N|B1)P(B1)}{P(N|B1)P(B1) + P(N|B2)P(B2) + (P(N|B3)P(B3)} = \frac{(0.297)(0.3)}{(0.297)(0.3) + (0.994)(0.2) + (0.990)(0.5)} = 0.1138

Hence the probability that a non-defective product is produced by machine B1 is 11.38%.

4 0
3 years ago
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