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k0ka [10]
3 years ago
10

The blades in a blender rotate at a rate of 7700 rpm. when the motor is turned off during operation, the blades slow to rest in

2.5 s. what is the angular acceleration as the blades slow down?
Physics
1 answer:
Tpy6a [65]3 years ago
7 0

Angular acceleration = (change in angular speed) / (time for the change)

Change in angular speed = (speed at the end) - (speed at the beginning)

For this fan, speed at the end = 7700 rpm, speed at the end = 0 .

Change in angular speed = -7700 rpm

Angular acceleration = (-7700 rpm) / (2.5 sec)

<em>Angular acceleration = -3,080 rev per minute / sec</em>

That's a perfectly good and true answer to the question, but the units are ugly.  We really need to fix the units, and convert them into something prettier before we hand in this assignment.

1 rev = 2π radians, and

1 minute = 60 seconds .

So

Angular acceleration =

(-3,080 rev/min-sec) · (2π rad/rev) · (1 min/60 sec)

AngAccel = (-3,080 · 2π · 1 / 60) · (rev·rad·min / min·sec·rev·sec)

AngAccel = ( -102 and 2/3 · π) · (rad/s²)

<em>AngAccel = -322.5 radian/s²</em>

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A long bar slides on two contact points and is in motion with velocity ν. A steady, uniform, magnetic field B is present. The in
fomenos

Answer:

The induced current in the resistor is I = BLv/R

Explanation:

The induced emf ε in the long bar of length, L in a magnetic field of strength, B moving with a velocity, v is given by

ε = BLv.

Now, the current I in the resistor is given by

I = ε/R where ε = induced emf in circuit and R = resistance of resistor.

So, the current I = ε/R.

substituting the value of ε the induced emf, we have

I = ε/R

I = BLv/R

So, the induced current through the resistor is given by I = BLv/R

5 0
3 years ago
5) Consider pushing a 50.0 kg box through a 5.00 m displacement on both a flat surface and up a
Svetach [21]

a) The work done by the gravitational force on the flat surface is zero

b) The work done by the gravitational force on the ramp is -634 J

c) The work done by the applied force on the flat surface is 500 J

d) The work done by the applied force on up along the ramp is 500 J

Explanation:

a)

The work done by a force is given by the equation

W=Fdcos \theta

where

F is the magnitude of the force

d is the dispalcement of the object

\theta is the angle between the direction of the force and of the displacement

In this problem, we want to calculate the work done by the gravitational force as the box is pushed across the flat ground.

We immediately notice that the gravitational force acts downward, while the displacement is horizontal: therefore, the angle between force and displacement is 90^{\circ}; this means that cos 90^{\circ}=0, and therefore, the work done is zero:

W=0

b)

In this case, the box is pushed along the ramp. We have:

F=mg=(50.0)(9.8)=490 N is the magnitude of the force of gravity, where

m = 50.0 kg is the mass of the box

g=9.8 m/s^2 is the acceleration of gravity

d = 5.00 m is the displacement of the box along the ramp

The ramp is inclined to the horizontal by 15.0^{\circ}, therefore the angle between the force of gravity and the displacement of the box (moving up along the ramp) is:

\theta=90^{\circ}+15^{\circ}=105^{\circ}

Therefore, the work done by gravity in this case is:

W=(490)(5.00)(cos 105^{\circ})=-634 J

c)

In this case, we want to calculate the work done by the force you apply as the box is pushed across the flat ground.

Here we have:

F = 100.0 N (force applied)

d = 5.00 m (displacement of the box)

\theta=0^{\circ} (the force is applied parallel to the flat surface, therefore force and displacement have same direction)

Therefore, the work done by the force you apply on the flat ground is:

W=(100.0)(5.00)(cos 0^{\circ})=500 J

d)

In this last case, we want to calculate the work done by the force you apply as the box is pushed up along the ramp.

This time we have:

F = 100.0 N (force applied is the same)

d = 5.00 m (displacement of the box is also the same)

\theta=0^{\circ} (the force is applied parallel to the ramp, therefore force and displacement have again same direction)

Therefore, the work done by the force you apply while pushing the box along the ramp is:

W=(100.0)(5.00)(cos 0^{\circ})=500 J

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8 0
4 years ago
A 200kg ball on the end of string is swung in horizontal circle with radius of 0.5m . The ball makes revolution every 2second th
kondaur [170]

The speed of the ball is 1.57 m/s

Explanation:

We start by calculating the angular speed of the ball, which is given by

\omega = \frac{2\pi}{T}

where

T is the period of revolution

For the ball in this problem,

T = 2 s

(since the ball makes 1 revolution every 2 seconds)

So, the angular speed is

\omega = \frac{2\pi}{T}=\frac{2\pi}{2}=\pi rad/s

Now we can calculate the speed of the ball by using

v=\omega r

where

r = 0.5 m is the radius of the circular path

Substituting,

v=(\pi)(0.5) = 1.57 m/s

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5 0
4 years ago
When flying in an airplane, you are most likely in which layer of the atmosphere? A. troposphere B. thermosphere C. stratosphere
abruzzese [7]
B because the thermometer is what it was based off
8 0
3 years ago
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Match the layer of Earth with its characteristic.
mote1985 [20]

Answer:

Explanation:

The Asthenosphere -- drives the movement in the plates

<em>It is a weak and flexible part of the upper mantle of the planet Earth.</em>

<em>It is located below the lithosphere. The depth of it is between 200 and 80 kilometers below the surface. It is usually solid but in some regions it is fluid. The temperature dictates the thickness of the Asthenosphere.</em>

The Core -- the hottest layer of the Earth.

<em>The inner Core of the Earth is a layer that's located in the core of it.  By definition, it is a rock-hard ball that has the radius of 1,220 kilometers, making it 20% of the Earth's radius and 70% of the Moon's radius. The samples are not discovered. It is believed that it has the composition of iron-nickel infusion along with other elements. The temperature is appx. 5430 °C, which is similar to the temperature of the surface of the Sun.</em>

Mesosphere -- contains the lower mantle

<em>By definition, it comes from the Greek word mesos, which means '' middle ''.</em>

<em>It is the third layer of the Earth. It is located above the stratosphere and below the thermosphere. The higher the altitude,  the lower the temperature. It ends in the coldest part of the Earth, Mesopause. And it begins at the Stratosphere.</em>

Lithosphere -- contains the tectonic plates

<em>By the definition, it is also a word that came from the Greek language. It comes from the word '' lithos '' which means '' rocky ''.</em>

<em>It is a hard, outer part of the Earth.</em>

<em>On the planet Earth, it is made out of the crust of the upper mantle.  The rocks from the Lithosphere are elastic.</em>

<em>They are two types of Lithosphere -- the oceanic Lithosphere and Continental Lithosphere.</em>

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6 0
3 years ago
Read 2 more answers
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