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Salsk061 [2.6K]

2 years ago

13

The pitch of the sound produced by a metal wire fixed between two points depends on A) how fast the wire vibrates. B) what type

of metal is used for the wire. C) how much force is used to pluck the wire. D) how far was the wire pulled from its normal resting position.

1 answer:

mrs_skeptik [129]2 years ago

7 0

It depends on A) how fast the wire vibrates because sound is produced by vibration

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How does our body get heat ? Explain in short .<br>For class 5 plz bro i need help

Murljashka [212]

Answer:

Thermogenesis:Your body's muscles, organs, and brain produce heat in a variety of ways

Explanation:

For example, muscles can produce heat by shivering. Hormonal thermogenesis: Your thyroid gland releases hormones to increase your metabolism. This increases the energy your body creates and the amount of heat it produces

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A car is moving at a velocity of 25 km/h and increases velocity to 1200 km/h in 2 min. what is the acceleration?

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Answer:

a = 2.72 [m/s2]

Explanation:

To solve this problem we must use the following kinematics equation:

$v_{f} =v_{o} + a*t$

where:

Vf = final velocity = 1200 [km/h]

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a = 35250.35 [km/h2]

if we convert these units to units of meters per second squared

$35250.35[\frac{km}{h^{2} }]*(\frac{1}{3600^{2} })*[\frac{h^{2} }{s^{2} } ]*(\frac{1000}{1} )*[\frac{m}{km} ] = 2.72 [\frac{m}{s^{2} } ]$

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2 years ago

How is energy transferred between two objects at different temperatures?

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When calculated energy transferred between objects use the definition of heat as

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An alpha particle (Î±), which is the same as a helium-4 nucleus, is momentarily at rest in a region of space occupied by an elec

vaieri [72.5K]

Answer:

Speed = 575 m/s

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Explanation:

Given :

Potential difference, U = $-3.45 \times 10^{-3} \ V$

Mass of the alpha particle, $m_{\alpha} = 6.68 \times 10^{-27} \ kg$

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So the potential difference for the alpha particle when it is accelerated through the potential difference is

$U=\Delta Vq_{\alpha}$

And the kinetic energy gained by the alpha particle is

$K.E. =\frac{1}{2}m_{\alpha}v_{\alpha}^2$

From the law of conservation of energy, we get

$K.E. = U$

$\frac{1}{2}m_{\alpha}v_{\alpha}^2 = \Delta V q_{\alpha}$

$v_{\alpha} = \sqrt{\frac{2 \Delta V q_{\alpha}}{m_{\alpha}}}$

$v_{\alpha} = \sqrt{\frac{2(3.45 \times 10^{-3 })(3.2 \times 10^{-19})}{6.68 \times 10^{-27}}}$

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The mechanical energy is conserved in the presence of the following conservative forces :

-- electrostatic forces

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Answer:

a) truc is C, b) correct result is the B

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For the time t = to γ

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Let's review the claims

A) False. It's the opposite

B) False

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D) False.

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ΔE = c² Δm

As in the process energy is released, for the law of conservation of the mass of energy to be fulfilled, the total mass of the products, He atom, must be reduced.

Therefore the correct result is the B

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3 years ago