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Minchanka [31]
3 years ago
6

39. When you heat a flask of water, how are you changing the ordered kinetic energy of the

Physics
1 answer:
valentina_108 [34]3 years ago
6 0

Answer:

The average kinetic energy of the molecules increases

Explanation:

The temperature of a substance is proportional to the average kinetic energy of the particles in the substance.

In fact, for an ideal gas for instance, there is the following relationship:

KE=\frac{3}{2}kT

where

KE is the average kinetic energy of the particles

k is the Boltzmann's constant

T is the absolute temperature of the gas

When we heat a substance (such as the flask of water in this problem), we are giving thermal energy to the particles of the substance; therefore, these particles will move faster on average, so their kinetic energy will increase (and the temperature of the substance will increase as well).

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A sixth grader moves down the hall at 1.2 m/s. When he sees a bunch of eighth graders coming, he
balandron [24]

Answer:

0.75m/s^2

Explanation:

3.6-1.2=2.4 m/s (Change in velocity)

2.4/3.2=0.75 m/s/s or m/s^2

5 0
3 years ago
Calculate the volume of this regular solid.
My name is Ann [436]

Answer:

2144.66 cm³

Explanation:

the formula is

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Think about the difference between thermal energy and temperature. How might the melting icicles gain energy without changing te
ivann1987 [24]

No temperature change occurs from heat transfer if ice melts and becomes liquid water (i.e., during a phase change). For example, consider water dripping from icicles melting on a roof warmed by the Sun. Conversely, water freezes in an ice tray cooled by lower-temperature surroundings.

Hope this helped you

5 0
3 years ago
Which process binds together sediment to form new rock?
vekshin1

Answer:

its cementation i got it correct

Explanation:

6 0
3 years ago
A 0.350kg bead slides on a curved fritionless wire,
LuckyWell [14K]

Answer:

h2 = 0.092m

Explanation:

From a balance of energy from point A to point B, we get speed before the collision:

m1*g*h-\frac{m1*V_B^2}{2}=0  Solving for Vb:

V_B=\sqrt{2gh}=6.56658m/s

Since the collision is elastic, we now that velocity of bead 1 after the collision is given by:

V_{B'}=V_B*\frac{m1-m2}{m1+m2} = \sqrt{2gh}* \frac{m1-m2}{m1+m2}=-1.34316m/s

Now, by doing another balance of energy from the instant after the collision, to the point where bead 1 stops, we get the distance it rises:

m1*g*h2-\frac{m1*V_{B'}^2}{2}=0 Solving for h2:

h2 = 0.092m

6 0
3 years ago
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