All categories

3 years ago

if the Horse and Rider have a combined mass of 572 kg what force would be required to accelerate them 5 kph per second

Physics

1 answer:

Vlad [161]3 years ago

8 0

Answer:

Force required to accelerate = 794.44 N

Explanation:

Force required = Mass of horse x Acceleration of horse

Mass of horse and rider, m= 572 kg

Acceleration of horse and rider, a = 5 kph per second

$=\frac{5*1000}{60*60} =1.39 m/s^2$

Force required = ma

= 572 x 1.39 = 794.44 N

Force required to accelerate = 794.44 N

You might be interested in

Which calculates the intensity of an electric field at a point where a 0.50 C charge experiences a force of 20. N?

tester [92]

Answer: $40\ N/C$

Explanation:

Given

Magnitude of charge is $q=0.5\ C$

Force experienced is $F=20\ N$

Electric field intensity is the electrostatic force per unit charge

$\therefore E=\dfrac{F}{q}\\\\\Rightarrow E=\dfrac{20}{0.50}\\\\\Rightarrow E=40\ N/C$

Thus, the electric field intensity is $40\ N/C$

6 0

3 years ago

What are some ways in which body fat can be measured

MissTica

I only know about the Water tank which is the most accurate. You place your body in it, and weights are added I think. Somehow some measurements are gathered to get your body fat weight. Online calculators exist, as well as electronic waves that are sent int your body, the echo is recorded and analyzed.

8 0

3 years ago

A rock is lifted by a machine to a height of 10m. If it has a mass of 22 kilograms

zmey [24]

Answer:

2156J

Explanation:

Given parameters:

Height of lift = 10m

Mass = 22kg

Unknown:

Work done by the machine = ?

Solution:

Work done is the force applied to move a body through a certain distance.

So;

Work done = Force x distance

Here;

Work done = mass x acceleration due to gravity x height

Work done = 22 x 9.8 x 10 = 2156J

5 0

3 years ago

Water (2510 g ) is heated until it just begins to boil. if the water absorbs 5.01×105 j of heat in the process, what was the ini

natka813 [3]

E=energy=5.09x10^5J = 509KJ
M=mass=2250g=2.25Kg 
C=specific heat capacity of water= 4.18KJ/Kg 
ΔT= change in temp= ? 
E=mcΔT 
509=(2.25)x(4.18)xΔT 
509=9.405ΔT 
ΔT=509/9.405=54.1degrees 
Initial temp = 100-54 = 46 degrees 
Hope this helps :)

5 0

3 years ago

For the airfoil and conditions in Problem 2.2, calculate the lift-to-drag ratio. Comment on its magnitude.

raketka [301]

Answer:

L/D= 112

Explanation:

Aerodynamics can be defined as the branch of dynamics which deals with the motion of air, their properties and the interaction between the air and solid bodies.

Aerodynamics law explains how an airplane is able to fly. There are four forces of flight, and they are; lift, weight, thrust and drag. The amount of lift generated by a wing divided by the aerodynamic drag is known as the lift to drag ratio.

Lift increases proportionally to the square of the speed.

The solutions to the question is the file attached to this explanation.

Lift,L= qC(l). S---------------------------(1).

and,

Drag,D = qC(d).S ----------------------(2).

Hence, Lift to drag ratio,L/D= C(l)/C(d).

Therefore, we have to compute various angle of attack.(check attached file)...

Then, (L/D) will then be equal to 112.

8 0

3 years ago