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matrenka [14]
4 years ago
15

Meaningful decisions are important to sustaining immersion, but it’s generally considered poor game design to constantly give th

e player “critical” decisions. Describe a game you know and how it asks the player to make a variety of decisions from the different levels of Tracy Fullerton’s Decision Scale.
Computers and Technology
1 answer:
bezimeni [28]4 years ago
7 0

Answer:

Explanation:

Meaningful decisions are important to sustaining immersion, but it's generally considered poor game design to constantly give the player "critical" decisions. Describe a game you know and how it asks the player to make a variety of decisions from the different levels of Tracy Fullerton's Decision Scale.

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Hi there, the only emails that go to the draft folder are the emails that you start to write and then you don't finish it so you can go back and finish writing it later.

Explanation:

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5)What are the differences in the function calls between the four member functions of the Shape class below?void Shape::member(S
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Answer:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

void Shape :: member ( Shape& s1, Shape& s2 ) const ; // pass by reference

void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

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Explanation:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

The s1 and s2 objects are passed by value as there is no * or & sign with them. If any change is made to s1 or s2 object, there will not be any change to the original object.

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

The s1 and s2 objects are passed by pointer as there is a * sign and not & sign with them. If any change is made to s1 or s2 object, there will be a change to the original object.

void Shape :: member ( Shape& s1, Shape& s2 ) const ; // pass by reference

The s1 and s2 objects are passed by reference  as there is a & sign and not * sign with them. If any change is made to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

The s1 and s2 objects are passed by reference  as there is a & sign and not * sign with them. The major change is the usage of const keyword here. Const keyword restricts us so we cannot make any change to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) const ; // plus the function is const

The s1 and s2 objects are passed by reference  as there is a & sign and not * sign with them. const keyword restricts us so we cannot make any change to s1 or s2 object as well as the Shape function itself.

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