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anastassius [24]
3 years ago
11

How ocean currents effect temperature and the amount of moisture of the air mass above coastlines

Physics
1 answer:
GarryVolchara [31]3 years ago
8 0
Hotter ocean tempatures mean more moisture in the dense air mass
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PLEASE HELP I NEED THIS ANSWER BADLY!!!!!!!! Explain how might an animal respond to stimuli as compared to a plant?
Misha Larkins [42]

Explanation:

Animas and plants react to stimuli which may come from other living things or from the environment. A stimulus causes the organism which receivs it to respond to it. Therefore the stimulus changes the behavior in the organism in some way.

5 0
3 years ago
(Select all that apply)
loris [4]

Answer: a. air pollution

c. hazardous wastes

d. potential reactor accident

e. water pollution

A nuclear energy is produced in a thermal power plant. A nuclear energy is produced in a nuclear reactor. In nuclear reactor nuclear fission reactions takes place in which an atoms absorbs energy from radiations and undergo fission and produces energy in the form of high intensity radiations along with heat. Although the fission reactions takes place in a nuclear reactor in a controlled way so that the radiation may not leak out from the reactor. The accidentally leak out radiations or explosion or bursting of the reactor due to uncontrolled thermal energy production can result in air pollution as the leak out air will cause bursting effects which will contaminate the air.

The nuclear waste are radioactive and are non-biodegradable these wastes are disposed off deep in geospheres and in water. They have potential to contaminate both land and water. Radioactive wastes can cause mutations in the genome of the organisms exposed to these wastes which generate deadly diseases and disorders.  Therefore, these wastes are hazardous.

5 0
3 years ago
Read 2 more answers
Why do we experience a high tide twice a day?
Veseljchak [2.6K]

Coastal areas experience two low tides and two high tides every lunar day, or 24 hours and 50 minutes. The two tidal bulges caused by inertia and gravity will rotate around the Earth as the moons position changes. These bulges represent high tides while the flat sides indicate low tides.

Over the course of 1 day, the position of the moon does not change very much compared to the rotation of the earth. As the earth rotates below the moon, one point on the earth will go through all levels of tide as the day passes by. Strongly attracted, middling, weakly attracted, and then middleagain. From our perspective it looks like "high, low, high, low." Or equivalently you can think about how the points below the moon and opposite the moon will be high tide, and as the earth rotates, those areas will change.

7 0
3 years ago
One of the primary goals of the Kepler space telescope is to search for Earth-like planets. Data gathered by the telescope indic
amid [387]

Answer:

85.62 m

168.75 years

101.04 years

Explanation:

L_0 = Length of ship = 143 m

v = Velocity of ship = 0.8c

c = Speed of light

s = Distance to Boralis orbit = 135 ly

Gamma value

\gamma=\dfrac{1}{\sqrt{1-\dfrac{v^2}{c^2}}}\\\Rightarrow \gamma=\dfrac{1}{\sqrt{1-\dfrac{0.8^2c^2}{c^2}}}\\\Rightarrow \gamma=1.67

Length contraction is given by

L=\dfrac{L_0}{\gamma}\\\Rightarrow L=\dfrac{143}{1.67}\\\Rightarrow L=85.62\ m

The length is 85.62 m

Time taken

t=\dfrac{s}{v}\\\Rightarrow t=\dfrac{135}{0.8}\\\Rightarrow t=168.75\ years

Time taken from the perspective one Earth is 168.75 years

Time dilation is given by

t'=\dfrac{t}{\gamma}\\\Rightarrow t'=\dfrac{168.75}{1.67}\\\Rightarrow t'=101.04\ years

The time taken from the perspective of the ship is 101.04 years

8 0
3 years ago
A block of weight mg sits on an inclined plane as shown in (Figure 1) . A force of magnitude F1 is applied to pull the block up
svlad2 [7]

Answer:

W = (F1 - mg sin θ) L,   W = -μ  mg cos θ L

Explanation:

Let's use Newton's second law to find the friction force. In these problems the x axis is taken parallel to the plane and the y axis perpendicular to the plane

Y Axis  

       N - W_{y} =

       N = W_{y}

X axis

       F1 - fr - Wₓ = 0

       fr = F1 - Wₓ

Let's use trigonometry to find the components of the weight

     sin θ = Wₓ / W

     cos θ = W_{y} / W

      Wₓ = W sin θ

      W_{y} = W cos θ

We substitute

      fr = F1 - W sin θ

Work is defined by

        W = F .dx

        W = F dx cos θ

The friction force is parallel to the plane in the negative direction and the displacement is positive along the plane, so the Angle is 180º and the cos θ= -1

         

        W = -fr x

        W = (F1 - mg sin θ) L

Another way to calculate is

         fr = μ N

         fr = μ W cos θ

the work is

         W = -μ  mg cos θ L

4 0
3 years ago
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