How ocean currents effect temperature and the amount of moisture of the air mass above coastlines

A disk is uniformly accelerated from rest with angular acceleration α. The magnitude of the linear acceleration of a point on th

solniwko [45]

Answer:

$a = R\alpha\sqrt{1 + \alpha^2t^4}$

Explanation:

As we know that the acceleration of a point on the rim of the disc is in two directions

1) tangential acceleration which is given as

$a_t = R\alpha$

2) Centripetal acceleration

$a_c = \omega^2 R$

here we know that

$\omega = \alpha t$

$a_c = (\alpha t)^2 R$

now we know that net linear acceleration is given as

$a = \sqrt{a_c^2 + a_t^2}$

so we have

$a = \sqrt{R^2\alpha^2 + R^2(\alpha t)^4}$

$a = R\alpha\sqrt{1 + \alpha^2t^4}$

4 0

3 years ago

A small metal sphere has a mass of 0.14 g and a charge of -22.0 nc . it is 10 cm directly above an identical sphere with the sam

Allushta [10]

For this problem, we use the Coulomb's law written in equation as:

F = kQ₁Q₂/d²
where
F is the electrical force
k is a constant equal to 9×10⁹
Q₁ and Q₂ are the charge of the two objects
d is the distance between the two objects

Substituting the values:

F = (9×10⁹)(-22×10⁻⁹ C)(-22×10⁻⁹ C)/(0.10 m)²
F = 0.0004356 N

4 0

3 years ago

_______ from the mantle rises and flows out through a vent onto Earth's surface as _______. This molten material, sometimes alon

anygoal [31]

Magma from the mantle rises and flows out through a vent onto Earth's surface as lava. This molten material, sometimes along with ash, cinders, and rock, builds up a mountain around the vent. The vent and its mountain together are called a sediment.

hope this helps

5 0

3 years ago

Read 2 more answers

Please help.......

IceJOKER [234]

Answer:

(L: Length, T: Time)

p: Dimension: L; unit: m

q: Dimension: L/T or (L)*(T)^-1; unit: m/s

r: Dimension: L/T^2 or (L)*(T)^-2; unit: m/s^2

Explanation:

since y is distance (Length), make all terms L distance.

p is same as y dimension ==> dimension: L; unit: m (meter)

qt dimension is L ==> q dimension :L/T; unit: m/s

rt^2 dimension is L ==> r dimension : L/T^2; unit: m/s^2

3 0

2 years ago

The 100-m dash can be run by the best sprinters in 10.0 s. A 66-kg sprinter accelerates uniformly for the first 45 m to reach to

irga5000 [103]

(a) 154.5 N

Let's divide the motion of the sprinter in two parts:

- In the first part, he starts with velocity u = 0 and accelerates with constant acceleration $a_1$ for a total time $t_1$ During this part of the motion, he covers a distance equal to $s_1 = 45 m$ , until he finally reaches a velocity of $v_1 = u + a_1t_1$ . We can use the following suvat equation:

$s_1 = u t_1 + \frac{1}{2}a_1t_1^2$

which reduces to

$s_1 = \frac{1}{2}a_1 t_1^2$ (1)

since u = 0.

- In the second part, he continues with constant speed $v_1 = a_1 t_1$ , covering a distance of $d_2 = 55 m$ in a time $t_2$ . This part of the motion is a uniform motion, so we can use the equation