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Answer:
The tensile stress on the wire is 550 MPa.
Explanation:
Given;
Radius of copper wire, R = 3.5 mm
extension of the copper wire, e = 5.0×10⁻³ L
L is the original length of the copper wire,
Young's modulus for copper, Y = 11×10¹⁰Pa.
Young's modulus, Y is given as the ratio of tensile stress to tensile strain, measured in the same unit as Young's modulus.

Therefore, the tensile stress on the wire is 550 MPa.
Answer: position (x) and time (t)
Explanation:
A body is said to be in motion when its position changes with time with respect to a stationary observer.
Following are the types of motion:
<u>Uniform motion</u>: When equal amount of distance is covered in equal intervals of time.
<u>Non-Uniform motion</u>: When unequal amount of distance is covered in equal intervals of time.
Motion can be of the following types as well:
<u>Rectilinear motion</u>: when object moves in a straight line.
<u>Circular motion</u>: when object moves in a curved path.
<u>Periodic motion</u>: when motion repeats itself in fixed intervals of time.
Thus, in order to define motion, only two variables are required: position and time. Measuring these variables can determine whether the object is in motion or not and the type of motion.
Answer:
The temperature must the ring be heated so that the sphere can just slip through is 106.165 °C.
Explanation:
For brass:
Radius = 1.3590 cm
Initial temperature = 23.0 °C
The sphere of radius 1.3611 cm must have to slip through the brass. Thus, on heating the brass must have to attain radius of 1.3611 cm
So,
Δ r = 1.3611 cm - 1.3590 cm = 0.0021 cm
<u>The linear thermal expansion coefficient of a metal is the ratio of the change in the length per 1 degree temperature to its length.</u>
<u>Thermal expansion for brass = 19×10⁻⁶ °C⁻¹</u>
Thus,

Also,

So,

Solving for final temperature as:

<u>Final temperature = 106.165 °C</u>