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vredina [299]
4 years ago
9

5. Describe the properties of each of these parts of the Earth’s interior: lithosphere, mantle, and core. What are they made of?

How hot are they? What are their physical properties?
Physics
1 answer:
Arisa [49]4 years ago
8 0
Hey there!

Okay so, the Lithosphere is made out of Earth’s outermost layer, which is composed of rocks in the crust and the upper mantle that behave as brittle solids.

The Mantle is made up of rock containing silicon, iron, magnesium, aluminum, oxygen and other minerals.

The Core has two parts. The solid inner core made up of iron. The outer core is surrounded by a liquid composed of a nickel-iron alloy.

I hope this helps!
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A soccer player kicks a rock horizontally off a 37 m high cliff into a pool of water. If the player hears the sound of the splas
Alchen [17]
<h2>Answer:</h2>

<em><u>(a). 16.741 m/s</u></em>

<em><u>(b). 15.75 m/s</u></em>

<h2>Explanation:</h2>

In the question,

Height of the cliff, h = 37 m

Time taken to reach the sound to us = 2.92 s

Speed of the sound in air at room temperature = 343 m/s

Now,

Let us say the speed of the ball = u m/s

So,

Time taken by the ball to reach at the bottom, t is given by,

t=\sqrt{\frac{2h}{g}}\\t=\sqrt{\frac{2\times 37}{9.8}}\\t=2.747\,s

So,

Splash is heard after = 2.92 s

So,

<u>Time taken by sound to travel the shortest distance along the hypotenuse of the triangle</u> thus formed is,

t = 2.92 - 2.747

t = 0.172 s

Now,

Distance traveled by sound is given by,

Distance=343\times 0.172\\Distance=59.02\,m

So,

In the triangle using the Pythagoras Theorem,

Horizontal distance traveled is,

D=\sqrt{59.02^{2}-37^{2}}\\D=45.99\,m

So,

Speed of throwing of ball is given by,

Distance=Speed\times Time\\45.99=u\times 2.747\\u=16.741\,m/s

<em><u>Therefore, the speed of the ball = 16.741 m/s.</u></em>

(b).

If,

Speed of sound = 331 m/s

So,

<u>Distance traveled by sound</u> is,

Distance=331\times 0.172\\Distance=56.932\,m

So,

Distance traveled in the horizontal by ball is,

Distance=\sqrt{56.932^{2}-37^{2}}\\Distance=43.269\,m

So,

Speed of the ball thrown is given by,

Speed=\frac{Distance}{Time}\\Speed=\frac{43.269}{2.747}\\Speed=15.75\,m/s

<em><u>Therefore, the speed of the ball = 15.75 m/s.</u></em>

8 0
3 years ago
To see why an MRI utilizes iron to increase the magnetic field created by a coil, calculate the current needed in a 400-loop-per
gtnhenbr [62]

Answer:

B = 4.059 x 10¹⁵ T

Explanation:

Given,

Number of loop, N = 400

radius of loop, r = 0.65 x 10⁻¹⁵ m

Current, I = 1.05 x 10⁴ A

Magnetic field at the center of the loop

B = \dfrac{\mu_0NI}{2R}

B = \dfrac{4\pi\times 10^{-7}\times 400 \times 1.05 \times 10^4}{2\times 0.65\times 10^{-15}}

B = 4.059 x 10¹⁵ T

7 0
3 years ago
A sample of gas at 23°C is placed in an expandable container with a volume of 23 mL. The gas is heated and expands to a volume o
myrzilka [38]

Based on the options given, the most likely answer to this query is B) The temperature must be converted to Kelvin. Meaning, the temperature should be in SI unit.

Thank you for your question. Please don't hesitate to ask in Brainly your queries. 
8 0
3 years ago
7. How long does it take a ball rolling down a hill to change its speed from 3 m/sec to 34.5 m/sec
lys-0071 [83]

The time elapsed is 9 seconds

Explanation:

The motion of the ball is a uniformly accelerated motion (a motion with constant acceleration), so we can use the following suvat equation:

v=u+at

where :

v is the final velocity  of the ball

u is the initial velocity

a is the acceleration

t is the time  elapsed

For the ball in this problem, we have:

u = 3 m/s is the initial velocity

v = 34.5 m/s is the final velocity

a=3.5m/s^2 is the acceleration

Solving for t, we find the time taken for this change in velocity:

t=\frac{v-u}{a}=\frac{34.5-3}{3.5}=9 s

Learn more about acceleration:

brainly.com/question/9527152  

brainly.com/question/11181826  

brainly.com/question/2506873  

brainly.com/question/2562700  

#LearnwithBrainly

8 0
3 years ago
Suppose that the acceleration of a model rocket is proportional to the difference between 160 ft/sec and the rocket's velocity.
Levart [38]

Answer:

Explanation:

Given ,

dv / dt = k ( 160 - v )

dv / ( 160 - v ) = kdt

ln ( 160 - v ) = kt + c , where c is a constant

when t = 0 , v = 0

Putting the values , we have

c = ln 160

ln ( 160 - v ) = kt + ln 160

ln ( 160 - v / 160 ) = kt

(160 - v ) / 160 = e^{kt}

1 - v / 160 = e^{kt }

v / 160 = 1 - e^{kt }

v = 160 ( 1 - e^{kt } )

differentiating ,

dv / dt = - 160k e^{kt }

acceleration a   = - 160k e^{kt }

given when t = 0 , a = 280

280 = - 160 k

k = - 175

a = - 160 x - 175 e^{kt}

a = 28000 e^{kt}

when a = 128  t = ?

128 = 28000 e^{kt}

e^{kt } = .00457

5 0
3 years ago
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