Cu + S ---> CuS
by reaction 1 mol 1 mol
from the problem 0.25 mol 0.25 mol
0.25 mol Cu
Answer:
C. disposition and condensation
Explanation:
Answer:
The precipitate was chromium hydroxide, which then reacted with more hydroxide to produce a soluble complex, Cr(OH)4
Explanation:
The following reaction takes place when chromium(III) nitrate reacts with NaOH:
+3 NaOH →
(s)+ 
The precipitate that is formed is chromium hydroxide, 
When more NaOH is added, the precipitate reacts with it which then results in the formation of a soluble complex ion:
(s) +
(aq) →
(aq)
is soluble complex ion
Answer:
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