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3 years ago

0 Balance the following equation: CO2 (g) + H2O (1) → C12H24012 (s) + O2 (g) +

Chemistry

1 answer:

Drupady [299]3 years ago

5 0

Explanation:

Answer: 12CO2(g) +12H2O(l)->C12H24O12(s)+12O2(g)

Once you make balancing equations don't disturb the given numbers because it is fix you need to solve by the side of the chemical name.

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3 years ago

What is a change in a substance that does not involve the identity of the substance

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3 years ago

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When methanol, CH 3 OH , is burned in the presence of oxygen gas, O 2 , a large amount of heat energy is released. For this reas

luda_lava [24]

<u>Answer:</u> The mass of methanol that must be burned is 24.34 grams

<u>Explanation:</u>

We are given:

Amount of heat produced = 581 kJ

For the given chemical equation:

$CH_3OH(g)+\frac{3}{2}O_2(g)\rightarrow CO_2(g)+2H_2O(l);\Delta H=-764kJ$

By Stoichiometry of the reaction:

When 764 kJ of heat is produced, the amount of methanol reacted is 1 mole

So, when 581 kJ of heat will be produced, the amount of methanol reacted will be = $\frac{1}{764}\times 581=0.7605mol$

To calculate mass for given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of methanol = 0.7605 moles

Molar mass of methanol = 32 g/mol

Putting values in above equation, we get:

$0.7605mol=\frac{\text{Mass of methanol}}{32g/mol}\\\\\text{Mass of methanol}=(0.7605mol\times 32g/mol)=24.34g$

Hence, the mass of methanol that must be burned is 24.34 grams

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3 years ago

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SpyIntel [72]

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0 Balance the following equation: CO2 (g) + H2O (1) → C12H24012 (s) + O2 (g) +​

0 Balance the following equation: CO2 (g) + H2O (1) → C12H24012 (s) + O2 (g) +