Answer: See photo
Explanation: There are a couple of ways to use velocity in an equation in the photo.
Given Information:
Inlet Temperature of hot air= Th₁ = 450K
Exit Temperature of hot air = Th₂ = 350K
Inlet Temperature of cold air = Tc₁ = 300K
Volume flow rate of hot air = vh = 0.02 m³/s
Volume flow rate of cold air = vc = 1 m³/s
Required Information:
Exit Temperature of cold air= Tc₂ = ?
Answer:
Exit Temperature of cold air = Tc₂ = 302 °C
Explanation:
In a heat exchanger, the cold air absorbs heat that is lost by the hot air,
Heat absorbed by cold air = Heat lost by hot air
Therefore, the exit temperature of the cold air is 302 °C or 575K
Note:
m = ρv
Where ρ is density of air and v is the volume flow rate and m is the mass flow rate.
cp is the specific heat capacity of air.
<u>D.</u>
For every action ther is an equal and opposite reaction.
equal in force, opposite in direction
According to Newton's first law of motion, the puck gradually slows down because friction would be acting on it.
<h3>What is Newton's first law?</h3>
Newton's first law of motion states that an object will remain at rest or move uniformly in a straight line unless acted upon by an external force.
According to this question, a hockey puck is hit with a large force. The puck moves at a high speed as it slides over the ice.
However, in accordance with the first law of motion proposed by Newton, the puck gradually slows down because friction would be acting on it.
Learn more about Newton's law at: brainly.com/question/974124
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Initial conditions
K is the spring constant
X is the compression of the spring