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Grace [21]
4 years ago
11

A bug splats against the windshield of a car traveling at high speeds down a backcountry road. Which statement correctly compare

s the objects' changes in momentum?
A. The bug's change in momentum is larger than the car's change in momentum.
B. The bug's change in momentum is smaller than the car's change in momentum.
C. The bug's change in momentum is equal to the car's change in momentum.
D. The question does not provide enough information. (The question should include whether the collision is elastic or inelastic.)
Physics
1 answer:
zvonat [6]4 years ago
6 0

Answer:

C. The bug's change in momentum is equal to the car's change in momentum.

Explanation:

As we know by Newton's 2nd law

F = \frac{\Delta P}{\Delta t}

here we have also know that when car hits the bug then force applied by wind shield on the bug is same as the force applied by the bug on the car's wind shield as per Newton's III law

F_{12} = F_{21}

so we know that

\frac{\Delta P_{12}}{\Delta t} = \frac{\Delta P_{21}}{\Delta t}

so we have

\Delta P_{12} = \Delta P_{21}

so correct answer will be

C. The bug's change in momentum is equal to the car's change in momentum.

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Answer:

The correct answer is d

Explanation:

In this exercise they ask us which statement is correct, for this we plan the solution of the problem, this is a Doppler effect problem, it is the frequency change due to the relative speed between the emitter and the receiver of sound.

The expression for the Doppler effect of a moving source is  

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From this expression we see that if the speed the sound source is different from zero feels a change in the  frequency.

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Answer:

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Explanation:

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