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stiks02 [169]
4 years ago
15

Leap years _____. happen because the Earth revolves around the sun in less than 365 days make up for the extra one-fourth day th

e Earth needs to orbit the sun add an extra day to the end of December, making the month 32 days long subtract a day from February, making the month only 27 days long
Physics
1 answer:
anzhelika [568]4 years ago
7 0

The Earth takes (365 and 1/4) days to orbit the sun.  That's the length of our 'year'.

Since it's not really possible to make our calendar a quarter of a day longer every year, we make the calendar a <u><em>whole</em></u> day longer every 4 years.

So "Leap years" make up for the extra one-fourth day the Earth takes to orbit the sun.

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Which of the following documents could be used to represent claims to financial assets?
stiks02 [169]
I think the correct answer would be passbooks. It can be used to prove one's financial assets. It holds record of all bank transactions done on that particular account. Basically, all withdrawals and deposits are recorded there. Hope this helped.
4 0
4 years ago
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I need question 5 please and correct any others if they’re wrong
Kryger [21]
The resistance would increase.
8 0
3 years ago
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A 2400-kg satellite is in a circular orbitaround a planet. The
Fofino [41]

Answer

given,

mass of satellite = 2400 Kg

speed of the satellite =  6.67 x 10³ m/s

acceleration of satellite = ?

gravitational force of the satellite will be equal to the centripetal force

F = \dfrac{mv^2}{r}

F = \dfrac{2400\times (6.67\times 10^3)^2}{r}

Assuming the radius of circular orbit = 8.92 x 10⁶ m

now,

F = \dfrac{2400\times (6.67\times 10^3)^2}{8.92\times 10^6}

F = 11970.11 N

acceleration,

a = \dfrac{F}{m}

a = \dfrac{11970.11}{2400}

  a = 4.98 m/s²

4 0
3 years ago
If you were to walk at a constant speed 20m/s for 30 seconds, how far would you walk?
lana [24]

Answer:

600m

Explanation:

30×20 at a constant speed is 600m.

6 0
4 years ago
An electric device, which heats water by immersing a resistance wire in the water, generates 50 cal of heat per second when an e
Oksi-84 [34.3K]

Answer:

0.69 ohm

Explanation:

Heat generated per second, H = 50 cal/s

Potential difference, V = 12 V

Let R is the resistance of coil.

The formula for the heat is given by

H = \frac{V^{2}}{R}t

50\times 4.186 = \frac{12^{2}}{R}\times 1

R = 0.69 ohm

3 0
3 years ago
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