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vaieri [72.5K]
2 years ago
10

Write each multiplecation setence as an aditon sentence 5X5=25 6X2=12

Mathematics
2 answers:
Vilka [71]2 years ago
7 0

Step-by-step explanation:

5+5+5+5+5

6+6

hope this helps

stira [4]2 years ago
3 0
5 + 5 + 5 + 5 + 5 = 25

6 + 6 = 12

Hope this helps :)
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7 0
3 years ago
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san4es73 [151]
1. 7 and -7 are both 7 units away from 0.  They are 14 units away from each other. Absolute value helps because rather than 7+(-7) being 0 absolute value makes anything positive so it becomes 7+7=14 to be able to count the units between the two.

2. 5 and -5 are both 5 units away from 0.  They are 10 units away from each other. Absolute value helps because rather than 5+(-5) being 0 absolute value makes anything positive so it becomes 5+5=10 to be able to count the units between the two.

3. 2 and -2 are both 2 units away from 0.  They are 4 units away from each other. Absolute value helps because rather than 2+(-2) being 0 absolute value makes anything positive so it becomes 2+2=4 to be able to count the units between the two.

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8 0
3 years ago
I need help with this someone very smart at math this algebra 2
Mrac [35]

Answer:

value if a =

\frac{5}{4}

Step-by-step explanation:

here's the solution :-

=》

\frac{ 2(\sqrt{m})  {}^{3} }{ \sqrt[4]{m} }

=》

\frac{2(m {}^{ \frac{1}{2}} ) {}^{3} }{ {m}^{ \frac{1}{4} } }

=》

\frac{2 {m}^{ \frac{3}{2} }} { {m}^{ \frac{1}{4} } }

=》

2m {}^{ \frac{3}{2}  -  \frac{1}{4} }

=》

2m {}^{ \frac{6 - 1}{4} }

=》

2m {}^{ \frac{5}{4} }

so, a = 5/4

6 0
2 years ago
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