Write each multiplecation setence as an aditon sentence 5X5=25 6X2=12
2 answers:
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Answer:
(a). 15
(b). 78
Step-by-step explanation:
Growth of the population of a fruit fly is modeled by
N(t) =
where t = number of days from the beginning of the experiment.
(a). For t = 0 [Initial population]
N(0) =
=
=
= 15
Initial population of the fruit flies were 15.
(b).Population of the fruit fly colony on 11th day.
N(11) =
=
=
=
=
= 77.82
≈ 78
On 11th day number of fruit flies colony were 78.
Answer:
Ninety-five percent of consumers in the U.S. consumed less than 63.59 gallons.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
The standard deviation is the square root of the variance, so
Also, the mean is 42.2, so
Ninety-five percent of consumers in the U.S. consumed less than how many gallons?
The 95th percentile, which is the value of X when Z has a pvalue of 0.95. So X when
Ninety-five percent of consumers in the U.S. consumed less than 63.59 gallons.