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Alisiya [41]
3 years ago
12

True or false describing a metal as malleable means that it can be pounded into a new shape

Physics
1 answer:
vampirchik [111]3 years ago
3 0
The answer is True.

Dictionary definition of <span>malleable. 
</span>
(of a metal or other material) able to be hammered or pressed permanently out of shape without breaking or cracking. 
You might be interested in
Which term refers to a variable that a scientist adjusts during an experiment?
azamat

Answer:

it’s c

Explanation:

5 0
3 years ago
On a windy day, the wind turbine transfers 78 W of power. Calculate the amount of energy the turbine transfers in 10s.​
tangare [24]

Answer:

Energy = 780 Joules

Explanation:

Given the following data;

Power = 78 Watts

Time = 10 seconds

To find the energy transferred;

Energy refers to the amount or quantity of power which is being consumed by an individual, group of people or organization over a specific period of time.

Mathematically, energy is given by the formula;

Energy = power * time

Energy = 78 * 10

Energy = 780 Joules

Therefore, the amount of energy the turbine transferred is 780 Joules

4 0
2 years ago
How does radiation help treat cancer?
sergejj [24]

Answer:

it cools down the cancer cells

Explanation:

The cancer cells are rapidly reproducing and when you cool it down it slows down the mutation/ reproduction process.

3 0
3 years ago
Read 2 more answers
On a frictionless horizontal air table, puck A (with mass 0.254 kg ) is moving toward puck B (with mass 0.367 kg ), which is ini
irinina [24]

Answer:

v_a=0.8176 m/s

\Delta K=0.07969 J - 0.0849 J = -0.00521 J

Explanation:

According to the law of conservation of linear momentum, the total momentum of both pucks won't be changed regardless of their interaction if no external forces are acting on the system.

Being m_a and m_b the masses of pucks a and b respectively, the initial momentum of the system is

M_1=m_av_a+m_bv_b

Since b is initially at rest

M_1=m_av_a

After the collision and being v'_a and v'_b the respective velocities, the total momentum is

M_2=m_av'_a+m_bv'_b

Both momentums are equal, thus

m_av_a=m_av'_a+m_bv'_b

Solving for v_a

v_a=\frac{m_av'_a+m_bv'_b}{m_a}

v_a=\frac{0.254Kg\times (-0.123 m/s)+0.367Kg (0.651m/s)}{0.254Kg}

v_a=0.8176 m/s

The initial kinetic energy can be found as (provided puck b is at rest)

K_1=\frac{1}{2}m_av_a^2

K_1=\frac{1}{2}(0.254Kg) (0.8176m/s)^2=0.0849 J

The final kinetic energy is

K_2=\frac{1}{2}m_av_a'^2+\frac{1}{2}m_bv_b'^2

K_2=\frac{1}{2}0.254Kg (-0.123m/s)^2+\frac{1}{2}0.367Kg (0.651m/s)^2=0.07969 J

The change of kinetic energy is

\Delta K=0.07969 J - 0.0849 J = -0.00521 J

3 0
3 years ago
Does the moon fall partly into earth's shadow when it is n "full"?
murzikaleks [220]
Yes, <span> the moon fall partly into earth's shadow when it is in its full size</span>
5 0
3 years ago
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