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marshall27 [118]
4 years ago
7

Difference between d.c and a.c

Physics
1 answer:
viva [34]4 years ago
5 0
Answer: In direct current (DC), the electric charge only flows in one direction.
Electric charge in alternating current (AC<span>), changes direction periodically. 

Hope this helps! :)</span>
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What do you do when ur dog is running away?
Alexxx [7]

Answer:

Try to chase it or try to put up missing posters if you cant him/her, i never had a dog but i would do that and ask neighbors if they know where the dog is at.

Explanation:

7 0
3 years ago
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An optical disk drive in your computer can spin a disk up to 10,000 rpm (about 1045 rad/s 1045 rad/s ). If a particular disk is
Scilla [17]

Answer:

The magnitude of the average angular acceleration of the disk is 4139.74\ rad/s^2.

Explanation:

Given that,

Angular velocity, \omega_i=968.7\ rad/s

The disk comes to rest, \omega_i=0

Time, t = 0.234 s

We need to find the magnitude of the average angular acceleration of the disk. It is given by change in angular velocity per unit time. So,

\alpha =\dfrac{\omega f}{t}\\\\\alpha =\dfrac{968.7\ rad/s}{0.234\ s}\\\\\alpha =4139.74\ rad/s^2

So, the magnitude of the average angular acceleration of the disk is 4139.74\ rad/s^2.

5 0
3 years ago
Sediment forms through _______________________ of rocks,
Anna71 [15]

Answer:

C

Explanation:

7 0
3 years ago
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Heather and Matthew take 45 s to walk eastward along a straight road to a store 72 m away. What is their average velocity?
vladimir1956 [14]

Answer:

v = 1.6 m/s

Explanation:

Given that,

Distance, d = 72 m

Time taken, t = 45 s

We need to find their average velocity. Average velocity of an object is given by total distance divided by total time taken.

v=\dfrac{d}{t}\\\\v=\dfrac{72\ m}{45\ s}\\\\v=1.6\ m/s

So, their average velocity is 1.6 m/s.

5 0
4 years ago
As a box slides down a ramp, friction does 23.0 joules of work. At the bottom of the ramp, the box has 3.8 joules of kinetic ene
tensa zangetsu [6.8K]

Answer:

The high of the ramp is 2.81[m]

Explanation:

This is a problem where it applies energy conservation, that is part of the potential energy as it descends the block is transformed into kinetic energy.

If the bottom of the ramp is taken as a potential energy reference point, this point will have a potential energy value equal to zero.

We can find the mass of the box using the kinetic energy and the speed of the box at the bottom of the ramp.

E_{k}=0.5*m*v^{2}\\\\where:\\E_{k}=3.8[J]\\v = 2.8[m/s]\\m=\frac{E_{k}}{0.5*v^{2} } \\m=\frac{3.8}{0.5*2.8^{2} } \\m=0.969[kg]

Now applying the energy conservation theorem which tells us that the initial kinetic energy plus the work done and the potential energy is equal to the final kinetic energy of the body, we propose the following equation.

E_{p}+W_{f}=E_{k}\\where:\\E_{p}= potential energy [J]\\W_{f}=23[J]\\E_{k}=3.8[J]\\

And therefore

m*g*h + W_{f}=3.8\\ 0.969*9.81*h - 23= 3.8\\h = \frac{23+3.8}{0.969*9.81}\\ h = 2.81[m]

8 0
3 years ago
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