Answer:
see below
Explanation:
The rate constant is missing in question, but use C(final) = C(initial)e^-kt = 0.200M(e^-k·10). Fill in k and compute => remaining concentration of reactant
Reactant at the left product at the rig
Answer:
why are anime and cartoons awesome? wt..f
Explanation:
I dont got that are you serious or making fun?
Answer:
The answer to your question is A.
Pure substances can not be broken down into others, so they cannot be molecules
Explanation:
