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Allisa [31]
3 years ago
15

Lainey bought a set of 20 markers for 6$ . What is the cost of 1 marker

Mathematics
2 answers:
alukav5142 [94]3 years ago
5 0

<em>Hope</em><em> </em><em>this</em><em> </em><em>w</em><em>i</em><em>l</em><em>l</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>.</em>

forsale [732]3 years ago
3 0

Answer: $0.3 or 30cents

Step-by-step explanation:

Total markers= 20

Total cost= $6

Cost of 1 marker= 6/20 = 3/10

Since 100cent makes 1 dollar= 3/10 × 100 = 30cents each

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Solve the triangle. B = 36°, a = 38, c = 18
Gelneren [198K]

Answer:

A ≈ 119.7°, b ≈ 25.7, C ≈ 24.3°

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A suitable app or calculator does this easily. (Since you're asking here, you're obviously not unwilling to use technology to help.)

_____

Given two sides and the included angle, the Law of Cosines can help you find the third side.

... b² = a² + c² - 2ac·cos(B)

... b² = 38² + 18² -2·38·18·cos(36°) ≈ 661.26475

... b ≈ 25.715

Then the Law of Sines can help you find the other angles. It can work well to find the smaller angle first (the one opposite the shortest side). That way, you can tell if the larger angle is obtuse or acute.

... sin(C)/c = sin(B)/b

... C = arcsin(c/b·sin(B)) ≈ 24.29515°

This angle and angle B add to less than 90°, so the remaining angle is obtuse. (∠A can also be found as 180° - ∠B - ∠C.)

... A = arcsin(a/b·sin(B)) ≈ 119.70485°

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