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brilliants [131]
3 years ago
11

TIMED! URGENT! REALLY APPRECIATE HELP!! TYSM!!!!!!

Physics
2 answers:
JulsSmile [24]3 years ago
8 0

Answer:

<em>d = 27.03 m</em>

Explanation:

<u>Constant Speed Motion </u>

An object travels at constant speed if the ratio of the distance traveled by the time taken is constant.

Expressed in a simple equation, we have:

\displaystyle v=\frac{d}{t}

Where  

v = Speed of the object

d = Distance traveled

t = Time taken to travel d.

From the equation above, we can solve for d:

d = v . t

It's required to find the distance traveled by someone walking at v=1.7 m/s for t=15.9 s. Substituting in the last equation:

d = 1.7 m/s * 15.9 s

d = 27.03 m

Diano4ka-milaya [45]3 years ago
3 0
The answer is 27.03 I just multiplied the two numbers
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3.27 moles of an ideal gas in a 50.0 L tank has a pressure of 171000 Pa. What is the temperature of the gas? (Unit=degrees C)
laiz [17]

The temperature of the gas is 41.3 °C.

Answer:

The temperature of the gas is 41.3 °C.

Explanation:

So on combining the Boyle's and Charles law, we get the ideal law of gas that is PV=nRT. Here P is the pressure, V is the volume, n is the number of moles, R is gas constant and T is the temperature. The SI unit of pressure is atm. So we need to convert 1 Pa to 1 atm, that is 1 Pa = 9.86923×10^{-6} atm. Thus, 171000 Pa = 1.6876 atm.

We know that the gas constant R = 0.0821 atmLMol–¹K-¹. Then the volume of the gas is given as 50 L and moles are given as 3.27 moles.

Then substituting all the values in ideal gas equation ,we get

1.6876×50=3.27×0.0821×T

Temperature = \frac{84.38}{0.268467} =314.3 K

So the temperature is obtained to be 314.3 K. As 0°C = 273 K,

Then 314.3 K = 314.3-273 °C=41.3 °C.

Thus, the temperature is 41.3 °C.

3 0
3 years ago
Consider a 2.54-cm-diameter power line for which the potential difference from the ground, 19.6 m below, to the power line is 11
tiny-mole [99]

Answer:

The line charge density is 1.59\times10^{-4}\ C/m

Explanation:

Given that,

Diameter = 2.54 cm

Distance = 19.6 m

Potential difference = 115 kV

We need to calculate the line charge density

Using formula of potential difference

V=EA

V=\dfrac{\lambda}{2\pi\epsilon_{0}r}\times\pi r^2

\lambda=\dfrac{V\times2\epsilon_{0}}{r}

Where, r = radius

V = potential difference

Put the value into the formula

\lambda=\dfrac{115\times10^{3}\times2\times8.8\times10^{-12}}{1.27\times10^{-2}}

\lambda=1.59\times10^{-4}\ C/m

Hence, The line charge density is 1.59\times10^{-4}\ C/m

4 0
3 years ago
How is the pressure of a gas related to its concentration of particles?A) Pressure will expand a gas, enlarging its volume and r
Lesechka [4]

Answer:

C) Pressure will compress a gas, reducing its volume and giving it a greater density and concentration of particles.

Explanation:

At constant temperature, pressure and volume are inversely related.

P V = constant

\Rightarrow P \propto \frac{1}{V}

As the pressure increases, the gas compresses, the particles come closer reducing the volume of gas.

As we know, with decrease in volume, density increases.

Density = \frac{Mass}{Volume}

Density \propto \frac{1}{Volume}

Thus, the pressure of a gas is directly related to concentration of particles. Increase in pressure causes increase in concentration of the particles.

8 0
3 years ago
Determine the gain in the potential energy when a 8.0 kg box is raised 17.2 m.
Marysya12 [62]

Answer:

<h2>The answer is 1376 J</h2>

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 10 m/s²

From the question we have

PE = 8 × 10 × 17.2

We have the final answer as

<h3>1376 J</h3>

Hope this helps you

6 0
3 years ago
Read 2 more answers
How do you move the decimal from megameters to meters?
Deffense [45]
The prefix "mega" means million.
Therefore
1 megameter = 10⁶ meters

That is,
1.0 megameter = 1,000,000.0 meters.

Answer:
The decimal is moved right by 6 places to convert a megameter to meters.
8 0
3 years ago
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