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g100num [7]
3 years ago
8

An object is placed exactly halfway between the Earth and moon. The object will fall toward the

Physics
2 answers:
Veronika [31]3 years ago
5 0
Earth as the earth has a higher mass and therefore a higher gravitational force upon the object.
mars1129 [50]3 years ago
5 0

Answer:

Force of Earth will be dominating and the object will fall towards Earth

Explanation:

As we know that

Mass of Earth

M_e = 5.98 \times 10^{24} kg

Mass of Moon

M_m = 7.35 \times 10^{22} kg

since we know that gravitational force depends on mass and the distance between two objects

so here if an object is placed midway between Moon and Earth then as we can see that mass of Earth is approx 100 times more than the mass of Moon

So here we can say that Force of Earth will be dominating and the object will fall towards Earth

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d1i1m1o1n [39]

Answer:

T = 60 s

Explanation:

There are 6 poles on the track which are equally spaced

so the angular separation between the poles is given as

\theta = \frac{2\pi}{6}

\theta = \frac{\pi}{3}

so the angular speed of the train is given as

\omega = \frac{\theta}{t}

\omega = \frac{\pi}{30} rad/s

now we have time period of the train given as

T = \frac{2\pi}{\omega}

T = \frac{2\pi}{\frac{\pi}{30}}

T = 60 s

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4 years ago
Which statement best describes the atoms of the gas neon?
Leya [2.2K]

Answer:

They:

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3 years ago
A hotel elevator ascends 200m with maximum speed of 5m/s. Its acceleration and deceleration both have a magnitude of 1.0m/s2. Pa
ValentinkaMS [17]

Answer:

45 s .

Explanation:

The accelerator will first accelerate , then move with uniform velocity and at last it will decelerate to rest .

displacement s = ?

acceleration a = 1 m /s²

Final speed v = 5 m/s

initial speed u = 0

v² = u² + 2as

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s = 12.5  m

B)  Let time of acceleration or deceleration be t

v = u + a t

5 = 0 + 1 t

t = 5 s

Similarly displacement during deceleration = 12.5 m

Total distance during uniform motion = 200 - ( 12.5 + 12.5 ) =  175 m .

velocity of uniform motion = 5 m /s

time during which there was uniform velocity = 175 / 5 = 35 s

Total time = 5 + 35 + 5 = 45 s .

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Determine the displacement of a plane that is uniformly accelerated from 66 m/s to 88 m/s in 12 sec
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Determined the displacement of a plane is 66 m:s
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