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marishachu [46]
3 years ago
6

Zinc metal reacts with hydrochloric acid to produce hydrogen gas and an aqueous solution of zinc(ii) chloride. what is the reduc

ing agent in this reaction? maybe prof. umbridge was right in trying to remove her.
Chemistry
1 answer:
Mila [183]3 years ago
4 0
Answer: zinc is the reducing agent.

Explanation:

1) Reducing agent is the agent that releases electrons, is oxidized (its oxidation number increases)   and causes the reduction of the other agent (the reduced spices reduces its oxidation state).

2) Chemical equation:

Zn(s) + HCl (aq) → H2(g) + ZnCl2(s)

3) determine the oxidation states of each spices

Zn (s): oxidation state = 0
Zn in ZnCls: oxidation state = + 2.

Therfore Zn was oxidized and is the reducing agen.

H in HCl: oxidtation state = +1

H in H2: oxidation state = 0

Therefore H2 was reduced (it is the oxidizing agent).
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snow_lady [41]

Solution:-

  • a=Carbon(c)
  • b=Nitrogen ion(N+)
  • c=Oxygen ion(O-)

Now

#1

Let's look at the EC of carbon(Z=6)

\\ \tt\longmapsto 1s^22s^22p^2

  • Valency is 4

Now.

3 electrons are shared(1 with H_3C and 2 with N+)

Hence

Electron left unshared=4-3=1

#2

Lets look at EC of Nitrogen(N),Z=7

\\ \tt\longmapsto 1s^22s^22p^3

  • Valency is 3
  • It has already shared 3 electrons

But

Its Cation i.e N+

  • Hence 1 electron it donated .Now it has valency 4

Hence

Electron left unshared=4-3=1

#3

Lets look at EC of Oxygen(Z=8)

\\ \tt\longmapsto 1s^22s^22p^4

  • Valency =2

But it is anion hence 1electron required more which us bonded

Hence

Number of electrons left unshared=0

5 0
3 years ago
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lubasha [3.4K]

Acceleration represented by the equation = Δv/Δt.

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A diffusion coefficient KG was determined for the diffusion of a gas A through a stagnant film B [KG = 0.88 mol//h-ft2-atm].
Angelina_Jolie [31]

Explanation:

Transfer of mass A into stagnant film B depends on the availability of driving force.

Whereas driving force is the pressure difference at the surface of A and the bulk.

As,       N_{A} \propto (P_{A1} - P_{A2})

           N_{A} = K_{G} \times (P_{A1} - P_{A2})

Therefore, putting the given values into the above formula as follows.

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Thus, we can conclude that the flux of A from a surface into a mixture of A and B is 0.132 mol/h.ft^{2}

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