In the reaction below how would adding more of product C affect the equilibrium of the system? A+B arrows both ways C+D
1 answer:
You might be interested in
Answer: 0.745 g of will be produced from 1.08 g of sodium sulfate
Explanation:
To calculate the moles :
is the limiting reagent as it limits the formation of product and
is the excess reagent.
According to stoichiometry :
3 moles of produce = 3 moles of
Thus 0.0076 moles of will require=
of
Mass of
Thus 0.745 g of will be produced from 1.08 g of sodium sulfate
Answer:
option D is correct
D. This solution is a good buffer.
Explanation:
TRIS (HOCH)
CNH
if TRIS is react with HCL it will form salt
(HOCH)
CNH
+ HCL ⇆ (HOCH
)
NH
CL
Let the reference volume is 100
Mole of TRIS is = 100 × 0.2 = 20
Mole of HCL is = 100 × 0.1 = 10
In the reaction all of the HCL will Consumed,10 moles of the salt will form
and 10 mole of TRIS will left
hence , Final product will be salt +TRIS(9 base)
H = Pk + log (base/ acid)
8.3 + log(10/10)
8.3