During the ball's flight up its velocity and acceleration vectors are in opposite direction and during the ball's flight down its velocity and acceleration vectors are in same direction.
- The velocity vector is always in the direction of motion of the object. So, during the ball's flight up its velocity vector is in the upward direction (90°) and during the ball's flight down its velocity vector is in the downward direction (270°).
- When there is a positive acceleration in the object the acceleration vector is in the direction of motion of the object. When there is a negative acceleration in the object the acceleration vector is in the opposite direction of motion of the object. So, during the ball's flight up its acceleration vector is in the downward direction (270°) and during the ball's flight down its acceleration vector is in the upward direction (90°).
Velocity vector is the rate of change of position of an object. Acceleration vector is the rate of change of velocity of an object.
Therefore, during the ball's flight up its velocity and acceleration vectors are in opposite direction and during the ball's flight down its velocity and acceleration vectors are in same direction.
To know more about velocity and acceleration vectors
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Answer:
In the first law ,an object will not change its motion unless a force acts on it. In the second law force on an object is equal to its mass times its acceleration. In the third law ,when two objects interact , they apply forces to each other of equal magnitude and opposite direction
Acceleration=Final velocity-Initial velocity /time.
Acceleration=a=4m/s².
Initial velocity= u= 44m/s
Final velocity=v= let it be v, since we are to look for the final velocity.
Time=t=10seconds.
Mathematically:
a=v-u/t
Substituting the givens into the equation.
4=v-44/10
cross multiply.
4×10 = v-44
40=v-44
40+44=v
v=84m/s
Answer:
The distance between the lighthouse and the ship
from the start position A = 5.08 miles
from the Final point B = 7.23 miles
Explanation:
Note: Refer the figure
Let the position of the lighthouse be 'L'
Given:
When the ship is at the position A, ∠DAL=37°
Now, when the ship sails through a distance of 2.5 i.e at position B
mathematically,
AB=2.5 miles
∠ABL=25°
Now,
∠DAL + ∠LAB = 180°
or
37° + ∠LAB = 180°
or
∠LAB = 180° - 37° = 143°
Also, In ΔLAB
∠LAB + ∠ABL + ∠ALB = 180°
or
143° + 25° + ∠ALB = 180°
or
∠ALB = 180° - 143° - 25° = 12°
Now using the concept of the sin law
In ΔLAB

or
AL = 5.08 miles
and,

or
BL = 7.23 miles
hence,
The distance between the lighthouse and the ship
from the start position A = 5.08 miles
from the Final point B = 7.23 miles
Please clarify the question, and add more information before I can answer that, I’d need to know the amount of carbon atoms.