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Sav [38]
4 years ago
5

A thermally isolated system is made up of a hot piece of aluminum and a cold piece of copper; the aluminum and the copper are in

thermal contact. The specific heat capacity of aluminum is more than double that of copper. Which object experiences the greater temperature change during the time the system takes to reach thermal equilibrium?
Physics
1 answer:
butalik [34]4 years ago
4 0

Answer:

copper will have more change in temperature as compare with aluminum

Explanation:

Hot piece of copper is made in contact with cold piece of aluminium

So here thermal energy transfer will take place from copper to aluminium

so by energy conservation we can say that heat given by copper is same as the heat absorbed by aluminium.

now we have

m_1s_1\Delta T_1 = m_2s_2\Delta T_2

here we know that

s_1 = specific heat capacity of copper

s_2 = specific heat capacity of aluminum

given that specific heat capacity of aluminium is more than double that of copper

so we can say

s_2 = 2s_1

so here if the mass of copper and aluminium is same then

\Delta T_1 = 2 \Delta T_2

so temperature change of copper is twice the temperature change of aluminium

So copper will have more change in temperature as compare with aluminum

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A ball is thrown vertically upward and then comes back down. During the ball's flight up and down, its velocity and acceleration
Dovator [93]

During the ball's flight up its velocity and acceleration vectors are in opposite direction and during the ball's flight down its velocity and acceleration vectors are in same direction.

  • The velocity vector is always in the direction of motion of the object. So, during the ball's flight up its velocity vector is in the upward direction (90°) and during the ball's flight down its velocity vector is in the downward direction (270°).
  • When there is a positive acceleration in the object the acceleration vector is in the direction of motion of the object. When there is a negative acceleration in the object the acceleration vector is in the opposite direction of motion of the object. So, during the ball's flight up its acceleration vector is in the downward direction (270°) and during the ball's flight down its acceleration vector is in the upward direction (90°).

Velocity vector is the rate of change of position of an object. Acceleration vector is the rate of change of velocity of an object.

Therefore, during the ball's flight up its velocity and acceleration vectors are in opposite direction and during the ball's flight down its velocity and acceleration vectors are in same direction.

To know more about velocity and acceleration vectors

brainly.com/question/13492374

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6 0
1 year ago
Write each of Newton's three laws of motion. Use your own wording.
12345 [234]

Answer:

In the first law ,an object will not change its motion unless a force acts on it. In the second law force on an object is equal to its mass times its acceleration. In the third law ,when two objects interact , they apply forces to each other of equal magnitude and opposite direction

5 0
2 years ago
a train has a velocity of 44 metre per second and an acceleration of 4 metre per second square. its velocity after 10 seconds is
myrzilka [38]

Acceleration=Final velocity-Initial velocity /time.

Acceleration=a=4m/s².

Initial velocity= u= 44m/s

Final velocity=v= let it be v, since we are to look for the final velocity.

Time=t=10seconds.

Mathematically:

a=v-u/t

Substituting the givens into the equation.

4=v-44/10

cross multiply.

4×10 = v-44

40=v-44

40+44=v

v=84m/s

7 0
3 years ago
The bearing of a lighthouse from a ship was found to be N 37 degrees E. After the ship sailed 2.5 miles due south, the new beari
ella [17]

Answer:

The distance between the lighthouse and the ship

from the start position A = 5.08 miles

from the Final point B = 7.23 miles

Explanation:

Note: Refer the figure

Let the position of the lighthouse be 'L'  

Given:

When the ship is at the position A, ∠DAL=37°

Now, when the ship sails through a distance of 2.5 i.e at position B

mathematically,

AB=2.5 miles

∠ABL=25°

Now,

∠DAL + ∠LAB = 180°

or

37° +  ∠LAB = 180°

or

∠LAB = 180° - 37° = 143°

Also, In ΔLAB

∠LAB + ∠ABL + ∠ALB = 180°

or

143° + 25° + ∠ALB = 180°

or

∠ALB = 180° - 143° - 25° = 12°

Now using the concept of the sin law

In ΔLAB

\frac{AL}{sin25^o}=\frac{2.5}{sin12^o}

or

AL = 5.08 miles

and,

\frac{BL}{sin143^o}=\frac{2.5}{sin12^o}

or

BL = 7.23 miles

hence,

The distance between the lighthouse and the ship

from the start position A = 5.08 miles

from the Final point B = 7.23 miles

5 0
3 years ago
Based on this how many Carbon<br> Atoms would be on the products <br> Side
pashok25 [27]
Please clarify the question, and add more information before I can answer that, I’d need to know the amount of carbon atoms.
8 0
3 years ago
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