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ozzi
3 years ago
13

Why are overuse injuries particularly frustrating set-backs?

Physics
2 answers:
olganol [36]3 years ago
7 0
Because they are caused by your exercise 
anastassius [24]3 years ago
4 0

Answer:

Because they are caused by the excess exercise and lack of rest to recover the body.

Explanation:

Over use injuries can be say that the inflammation of the connecting tissues which attaches the bones to the muscles. They can be occur if someone does not modify his or her workout after a break.

These injuries particularly are frustrating set backs because you are not give a much time of rest to your body to recover from these injuries.

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What is gravity’s role in tides?
kotegsom [21]

The relationship between the masses of the Earth, moon and sun and their distances to each other play critical roles in affecting tides

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3 years ago
Read 2 more answers
How does the type of medium affect a sound wave?
Llana [10]

The type of medium affects a sound wave as sound travels with the help of the vibration in particles. As different mediums have different amount and size of particles, for example, the speed of sound is faster through solid than liquid as solids have closely packed particles whereas liquids are loosely packed. Therefore the vibration is quicker in solids than liquids.

Hope it helps you! :)

7 0
3 years ago
Estimate (a) the maximum, and (b) the minimum thermal conductivity values (in W/m-K) for a cermet that contains 83 vol% carbide
velikii [3]

Answer:

  k_max = 31.82 w/mk

  k_min  = 17.70 w/mk

Explanation:

a) the maximum thermal conductivity is given as

k_{max} = k_m*v_m + k_p*v_p

where k_m is thermal conductvitiy of metal

k_p is thermal conductvitiy of carbide

v_m = proportion of metal in the cement = 0.17

v_p = proportion of carbide in the cement = 0.83

            = 66*0.17 + 28*0.83

           k_max = 31.82 w/mk

b) the minimum thermal conductivity is given as

k_{min} = \frac{k_{carbide}* k_{metal}}{k_{metal} v_{carbide} +k_{metal} v_{carbide}}

          = \frac{28+66}{28*0.17 +66*0.83}

       k_min  = 17.70 w/mk

7 0
3 years ago
Help me guys<br><br>Class IX​
goldfiish [28.3K]

Answer:

with right hand grip rule

3. A- south

B- north

C- north

D- south

E- south

F- north

sorry idk what 1st & 2nd question means

4 0
3 years ago
A person is hauling their taco stand and it takes 3,500 Joules of work to stop the taco stand. What force was exerted on the tac
Lapatulllka [165]

Given the work done, the force exerted on the taco stand through the given distance is 2.3 × 10³ Newtons.

<h3>What is Work done?</h3>

Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;

W = f × d

Where f is force applied and d is distance travelled.

Given that;

  • Work done W = 3500J = 3500kgm²/s²
  • Distance covered d = 1.5m
  • Force applied F = ?

W = f × d

3500kgm²/s² = f × 1.5m

f = 3500kgm²/s² ÷ 1.5m

f = 2.3 × 10³ kgm/s²

f = 2.3 × 10³ N

Given the work done, the force exerted on the taco stand through the given distance is 2.3 × 10³ Newtons.

Learn more about work done here: brainly.com/question/26115962

#SPJ1

3 0
2 years ago
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