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3 years ago

Why are overuse injuries particularly frustrating set-backs?

Physics

2 answers:

olganol [36]3 years ago

7 0

Because they are caused by your exercise

anastassius [24]3 years ago

4 0

Answer:

Because they are caused by the excess exercise and lack of rest to recover the body.

Explanation:

Over use injuries can be say that the inflammation of the connecting tissues which attaches the bones to the muscles. They can be occur if someone does not modify his or her workout after a break.

These injuries particularly are frustrating set backs because you are not give a much time of rest to your body to recover from these injuries.

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If a player through a basketball to the target with an initial velocity of 17 m/s making an angle of 30 degrees with the horizon

Svetllana [295]

Answer:

The final position made with the vertical is 2.77 m.

Explanation:

Given;

initial velocity of the ball, V = 17 m/s

angle of projection, θ = 30⁰

time of motion, t = 1.3 s

The vertical component of the velocity is calculated as;

$V_y = Vsin \theta\\\\V_y = 17 \times sin(30)\\\\V_y = 8.5 \ m/s$

The final position made with the vertical (Yf) after 1.3 seconds is calculated as;

$Y_f = V_yt - \frac{1}{2}g t^2\\\\Y_f = (8.5 \times 1.3 ) - (\frac{1}{2} \times 9.8 \times 1.3^2)\\\\Y_f = 11.05 \ - \ 8.281\\\\Y_f = 2.77 \ m$

Therefore, the final position made with the vertical is 2.77 m.

3 0

3 years ago

A proton moving at 8.00 106 m/s through a magnetic field of magnitude 1.72 T experiences a magnetic force of magnitude 7.20 10-1

gladu [14]

Answer:

19.1 deg

Explanation:

v = speed of the proton = 8 x 10⁶ m/s

B = magnitude of the magnetic field = 1.72 T

q = magnitude of charge on the proton = 1.6 x 10⁻¹⁹ C

F = magnitude of magnetic force on the proton = 7.20 x 10⁻¹³ N

θ = Angle between proton's velocity and magnetic field

magnitude of magnetic force on the proton is given as

F = q v B Sinθ

7.20 x 10⁻¹³ = (1.6 x 10⁻¹⁹) (8 x 10⁶) (1.72) Sinθ

Sinθ = 0.327

θ = 19.1 deg

4 0

3 years ago

Guys No one's answering my question so sad! Once again I'm asking the same question –Here

nexus9112 [7]

For the front glass of the car to get wet, $V_c \geq 10 \ m/s$ .

The given parameters:

<em>Speed of the car, = Vc</em>
<em>Speed of the rain, = 10 m/s</em>

The relative velocity of the car with respect to the falling rain is calculated as;

$V_{C/R} = V_C- V_R$

If the speed of the car equals the speed of the rain, the rain will fall behind the car.
If the speed of the rain is greater than speed of the car, the rain will fall far in front of the car.
If the speed of the car is greater than speed of the rain, the rain will fall on the car.

Thus, for the front glass of the car to get wet, $V_c \geq 10 \ m/s$ .

Learn more about relative velocity here: brainly.com/question/17228388

8 0

3 years ago

Thought Experiment: A monkey escapes from a zoo and climbs a tree. After failing to entice the monkey down, a zookeeper fires a

Andreyy89

Explanation:

When bullet is shot towards the monkey then let say the distance of monkey from the bullet is "d"

so we can find the time to reach the bullet to the monkey

$t = \frac{d}{vcos\theta}$

Now similarly we can find the vertical displacement of the bullet in the same time

$\Delta y = vsin\theta t - \frac{1}{2}gt^2$

$\Delta y = v sin\theta (\frac{d}{vcos\theta}) - \frac{1}{2}gt^2$

so it is given as

$\Delta y = d tan\theta - \frac{1}{2}gt^2$

here if the monkey is initially at height H above the ground at given angle then we can say

$H = dtan\theta$

so we can say that

$\Delta y = H - \frac{1}{2}gt^2$

So if at the same time monkey will fall down then the height of monkey from ground after time "t" is given as

$\Delta y = H - \frac{1}{2}gt^2$

so here bullet will hit the monkey as both monkey and bullet are at same position.

3 0

3 years ago

How potential and kinetic energy changed during the spacecraft launches.

LenaWriter [7]

Answer:

Have a blessed day!

Explanation:

The energy to launch the spacecraft came from moving the spacecraft against the magnetic force. The energy used to move a magnet against a magnetic force is stored as potential energy in the magnetic field. This magnetic force can convert potential energy stored in the magnetic field to kinetic energy.

Please give brainliest!

4 0

2 years ago

Read 2 more answers