A horse shoe magnet is placed on a mass balance such that a uniform magnetic field of magnitude B runs between it from North to
South. A coil of resistance R is connected to a battery which supplies a potential difference of V across the coil and is suspended such that a section of the coil of length L meters lies between it with current running from East to West. The mass balance measures a mass of M.
1. What is the measured change in mass due to the effect of Fmag?
2. What is the total measured mass of the magnets? Keep in mind the effect of Newton's third law.
1. What is the measured change in mass due to the effect of Fmag?
2. What is the total measured mass of the magnets? Keep in mind the effect of Newton's third law.
1 answer:
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Answer:
k = 2.279
Explanation:
Given:
Magnitude of charge on each plate, Q = 172 μC
Now,
the capacitance, C of a capacitor is given as:
C = Q/V
where,
V is the potential difference
Thus, the capacitance due to the charge of 172 μC will be
C =
Now, when the when the additional charge is accumulated
the capacitance (C') will be
C' =
or
C' =
now the dielectric constant (k) is given as:
substituting the values, we get
or
k = 2.279