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Effectus [21]
2 years ago
8

A horse shoe magnet is placed on a mass balance such that a uniform magnetic field of magnitude B runs between it from North to

South. A coil of resistance R is connected to a battery which supplies a potential difference of V across the coil and is suspended such that a section of the coil of length L meters lies between it with current running from East to West. The mass balance measures a mass of M.
1. What is the measured change in mass due to the effect of Fmag?
2. What is the total measured mass of the magnets? Keep in mind the effect of Newton's third law.

Physics
1 answer:
rjkz [21]2 years ago
7 0

Answer:

Explanation:

FIND THE SOLUTION BELOW

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Answer:

(a) 41.75m/s

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Explanation:

Let:

 Distance, D = 89m

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With the distance formula, which is

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89 = \frac{1}{2}×9.8×t^{2}

With the equation above, we can solve for t:

t=\sqrt{\frac{89(2)}{9.8}} \\t=\sqrt{\frac{178}{9.8} } \\t=\sqrt{18.16} \\t=4.26 seconds

Now that we have solved t, we can use the following velocity formula to solve for v:

v = u + at, where a is also equals to g, so we have

v = u + gt

By substituting u = 0, g = 9.8, and t = 4.26,

We have:

v = 0 + 9.8(4.26)\\v = 41.75m/s

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