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3 years ago

Order the seven basic spectral types from hottest to coldest.

Physics

1 answer:

vfiekz [6]3 years ago

8 0

Answer:

There are basically seven spectral types which are used for classifying the stars and it is arranged in the order of increasing temperature from the hottest temperature to the coldest division are: O, B, A, F, G, K, and M. These categories are basically divided into the sub category in the spectral where O is the hottest type and M is the coldest type.

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An automobile is traveling away from Jill and towards Jack. The horn is honking, producing a sound wave.

wlad13 [49]

Answer:

a. The sound will travel at the speed to both Jill and Jack

b. Jack

Explanation:

a. Doppler effect describes how the frequency of a sound wave changes with regards to an observer that has relative motion to the sound source;

The Doppler effect is given by the following formula;

For a sound that is moving away, as observed by Jill, we have;

$f' = \dfrac{(v - v_0)}{(v + v_s)} \cdot f = \dfrac{v }{(v + v_s)} \cdot f$

For approaching sound, as observed by Jack, we have;

$f' = \dfrac{(v + v_0)}{(v - v_s)} \cdot f = \dfrac{v }{(v - v_s)} \cdot f$

Where;

f = The sound wave's actual frequency

f' = The frequency of the moving sound to the observer

v = The speed of the sound wave

v₀ = The observer's velocity = 0

$v_s$ = The velocity of the source (the automobile honking) of the sound wave

From the above equation, we have that the speed of sound, 'v', is the same to both the source, and the observer although the frequency, and therefore, the wavelength of the sound alternatively increases or decreases

b. From the Doppler effect equation, the person who will hear the highest frequency is given by the formula for the frequency when the sound is approaching the observer, which has the lower denominator

Therefore, given that the automobile is travelling towards Jack, jack will hear the higher frequency

5 0

3 years ago

This term refers to an intense and irrational fear of people from another country.

mel-nik [20]

xenofobia o racismo o al menos eso nos lo explico nuestro profesor

8 0

3 years ago

Read 2 more answers

3 a A motorcyclist starts from rest and reaches

andrew-mc [135]

The acceleration of the body is 2 m/s^2 while the deceleration is - 1.2 m/s^2.

<h3>What is the acceleration?</h3>

Let us recall that the acceleration is the change in the speed of a body with time. We have been told that the body accelerates for 3s and then decelerates to 2s. This implies that the total time that the object spent in motion is 5 s.

Thus;

v = u + at

v = final velocity

u = initial velocity

a = acceleration

t = time taken

v - u/t = a

a = 6 - 0/3

= 2 m/s^2

Again;

v - u/t = a

a = 0 - 6/5

a = - 1.2m/s^2

Learn more about acceleration:brainly.com/question/12550364

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7 0

2 years ago

Location C is 0.02 m from a small sphere which has a charge of 3 nanocoulombs uniformly distributed on its surface. Location D i

kkurt [141]

The change in potential along a path from C to D due to a small charged sphere is 900 V.

Given:

Charge, Q = 3 nC = 3 × 10⁻⁹ C

Distance between the sphere and point C, r₁ = 0.02 m

Distance between the sphere and point D, r₂ = 0.06 m

Calculation:

We know that the electric potential is given as:

V = k Q/r - (1)

where, V is the electric potential

k is Coulomb's force constant

Qis the charge on the sphere

r is the separation distance

The electric potential at point C due to charged sphere can be given as:

V₁ = k Q/r₁

= (9×10⁹ Nm²/C²) [(3 × 10⁻⁹ C)/(0.02 m)]

= 1350 V

The electric potential at point D due to charged sphere can be given as:

V₂ = k Q/r₂

= (9×10⁹ Nm²/C²) [(3 × 10⁻⁹ C)/(0.06 m)]

= 450 V

Now, the change in potential along the path from C to D can be calculated as:

ΔV = V₂ - V₁

= 450 V - 1350 V

= -900 V

The negative sign indicates that the work is done against the electric field in moving the charge from C to D.

Therefore, the change in potential along a path from C to D is 900 V against the direction of the electric field.

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2 years ago

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A major process by which the Sun's energy is transported around the Earth system?

Setler79 [48]

Is it Conduction. Here's my theory e<span>nergy is transferred between the earth's surface and the atmosphere by Conduction, Convection and Radiation.</span>

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3 years ago