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3 years ago

Please help. Solve 2x - 8 < 7.

Mathematics

2 answers:

kotegsom [21]3 years ago

4 0

ANSWER

The correct answer is C

EXPLANATION

The given inequality is:

$2x - 8 \: < \: 7$

Group the constant terms on the right hand side to get;

$2x \: < \: 7 + 8$

Simplify the right hand side

$2x \: < \: 15$

Divide both sides by 2

$x \: < \: \frac{15}{2}$

{x|x<15/2}

The correct answer is C

hram777 [196]3 years ago

4 0

Answer:

$\large\boxed{\left\{x\ |\ x$

Step-by-step explanation:

$2x-8$

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What is the equation of the line that passes through point (4, 12) and has a y-intercept of —2?

zmey [24]

Answer:

Step-by-step explanation:

The slope-intercept form of an equation of a line:

m - slope

b - y-intercept

We have y-intercept b = -2. Substitute:

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3 years ago

Read 2 more answers

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FrozenT [24]

Answer:

The answer is B: (1,2)

Step-by-step explanation:

(solved using elimination method)

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x+y=-1

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(x,y)=(1,2)

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3 years ago

Craig score p point in a game. marla score twice as many point as craig but 5 fewer than nelson score. how man point did nelson

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3 years ago

A machine fills containers with 35 ounces of raisins

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What’s the question?

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3 years ago

A trough of water is 20 meters in length and its ends are in the shape of an isosceles triangle whose width is 7 meters and heig

Vaselesa [24]

Answer:

a) Depth changing rate of change is $0.24m/min$ , When the water is 6 meters deep

b) The width of the top of the water is changing at a rate of $0.17m/min$ , When the water is 6 meters deep

Step-by-step explanation:

As we can see in the attachment part II, there are similar triangles, so we have the following relation between them $\frac{3.5}{10} =\frac{a}{h}$ , then $a=0.35h$ .

a) As we have that volume is $V=\frac{1}{2} 2ahL=ahL$ , then $V=(0.35h^{2})L$ , so we can derivate it $\frac{dV}{dt}=2(0.35h)L\frac{dh}{dt}$ due to the chain rule, then we clean this expression for $\frac{dh}{dt}=\frac{1}{0.7hL}\frac{dV}{dt}$ and compute with the knowns $\frac{dh}{dt}=\frac{1}{0.7(6m)(20m)}2m^{3}/min=0.24m/min$ , is the depth changing rate of change when the water is 6 meters deep.

b) As the width of the top is $2a=0.7h$ , we can derivate it and obtain $\frac{da}{dt}=0.7\frac{dh}{dt} =0.7*0.24m/min=0.17m/min$ The width of the top of the water is changing, When the water is 6 meters deep at this rate

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3 years ago