Answer:
50 kg water.
Step-by-step explanation:
We have been given that the number of kilograms of water in a human body varies directly as the mass of the body.
We know that two directly proportional quantities are in form 
, where y varies directly with x and k is constant of variation.
We are told that an 87-kg person contains 58 kg of water. We can represent this information in an equation as:
Let us find the constant of variation as:
The equation 
represents the relation between water (y) in a human body with respect to mass of the body (x).
To find the amount of water in a 75-kg person, we will substitute 
in our given equation and solve for y.
Therefore, there are 50 kg of water in a 75-kg person.
Answer:
Step-by-step explanation:
x
2
+
x
−
6
=
(
x
+
3
)
(
x
−
2
)
x
2
−
3
x
−
4
=
(
x
−
4
)
(
x
+
1
)
Each of the linear factors occurs precisely once, so the sign of the given rational expression will change at each of the points where one of the linear factors is zero. That is at:
x
=
−
3
,
−
1
,
2
,
4
Note that when
x
is large, the
x
2
terms will dominate the values of the numerator and denominator, making both positive.
Hence the sign of the value of the rational expression in each of the intervals
(
−
∞
,
−
3
)
,
(
−
3
,
−
1
)
,
(
−
1
,
2
)
,
(
2
,
4
)
and
(
4
,
∞
)
follows the pattern
+
−
+
−
+
. Hence the intervals
(
−
3
,
−
1
)
and
(
2
,
4
)
are both part of the solution set.
When
x
=
−
1
or
x
=
4
, the denominator is zero so the rational expression is undefined. Since the numerator is non-zero at those values, the function will have vertical asymptotes at those points (and not satisfy the inequality).
When
x
=
−
3
or
x
=
2
, the numerator is zero and the denominator is non-zero. So the function will be zero and satisfy the inequality at those points.
Hence the solution is:
x
∈
[
−
3
,
−
1
)
∪
[
2
,
4
)
graph{(x^2+x-6)/(x^2-3x-4) [-10, 10, -5, 5]}
<span>y=375/x, so when x=1, y=375</span>
Yes ok doubling dimensions
